A student conducts a titration using NaOH (strong base) as the titrant to determine the concentration of the formic acid (weak acid). From this titration the student determines that the concentration of sodium formate (salt) at the equivalence point is 0.00250 M. Given the pKa of formic acid is 3.75 and the auto ionisation constant for water (Kw) is 10-14. Calculate the pH at the equivalence point using the following equation. pH = 1/2pKw + 1/2pKa + 1/2logc where Kw = auto ionisation constant for water (10-14) Ka = acid dissociation constant for the weak acid c = concentration of the salt (M)
A student conducts a titration using NaOH (strong base) as the titrant to determine the concentration of the formic acid (weak acid). From this titration the student determines that the concentration of sodium formate (salt) at the equivalence point is 0.00250 M.
Given the pKa of formic acid is 3.75 and the auto ionisation constant for water (Kw) is 10-14.
Calculate the pH at the equivalence point using the following equation.
pH = 1/2pKw + 1/2pKa + 1/2logc
where Kw = auto ionisation constant for water (10-14)
Ka = acid dissociation constant for the weak acid
c = concentration of the salt (M)
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