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8. An indicator with Ka = 6.45 X 10-5 is yellow in acid and blue in base. Showing a calculation for the ratio of [In ]/[HIn] and indicate the color you expect for each. a. A solution of 0.125 M HCl. b. A solution of 0.125 M NaC2H3O2 (Ka HC2H3O2 = 1.80 X 105) c. A solution of 0.125 M KOH d. A solution of 0.125 M NH3 (Kp NH3 = 1.80 X 105) %3D

8. An indicator with Ka = 6.45 X 10-5 is yellow in acid and blue in base. Showing a calculation for the ratio of [In ]/[HIn] and indicate the color you expect for each. a. A solution of 0.125 M HCl. b. A solution of 0.125 M NaC2H3O2 (Ka HC2H3O2 = 1.80 X 105) c. A solution of 0.125 M KOH d. A solution of 0.125 M NH3 (Kp NH3 = 1.80 X 105) %3D

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.88QP: A 0.400-g sample of propionic acid was dissolved in water to give 50.0 mL of solution. This solution...
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8. An indicator with Ka = 6.45 X 105 is yellow in acid and blue in base. Showing a calculation for the ratio of [In]/[HIn] and indicate the color you expect for each. a. A solution of 0.125 M HCI. b. A solution of 0.125 M NaC,H3O2 (Ka HC2H302 = 1.80 X 105) %3D c. A solution of 0.125 M KOH d. A solution of 0.125 M NH3 (Kb NH3 = 1.80 X 105) e. The equivalence point of a titration of the solution in (b) with and equal concentration of HCI (aq).
Transcribed Image Text:8. An indicator with Ka = 6.45 X 105 is yellow in acid and blue in base. Showing a calculation for the ratio of [In]/[HIn] and indicate the color you expect for each. a. A solution of 0.125 M HCI. b. A solution of 0.125 M NaC,H3O2 (Ka HC2H302 = 1.80 X 105) %3D c. A solution of 0.125 M KOH d. A solution of 0.125 M NH3 (Kb NH3 = 1.80 X 105) e. The equivalence point of a titration of the solution in (b) with and equal concentration of HCI (aq).
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