To 1.28L of 0.378M NaOH, you add 3.5OL of a second NaOH solution of an unknown concentration. The resulting solution is titrated and determined to be 0.906M. Assuming the volumes are additive, calculate the molarity of the second NaOH solution. HINT: Since the volumes are additive, we have V1+V2 = V3. There just may be an equation on your supplemental sheet that you can use here.

To 1.28L of 0.378M NaOH, you add 3.5OL of a second NaOH solution of an unknown concentration. The resulting solution is titrated and determined to be 0.906M. Assuming the volumes are additive, calculate the molarity of the second NaOH solution. HINT: Since the volumes are additive, we have V1+V2 = V3. There just may be an equation on your supplemental sheet that you can use here.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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