3. Calculate the molarity of acetic acid in the diluted vinegar sample using the calculated moles of HC,H;0, in the 15.00 mL diluted vinegar sample. Remember to find molarity the volume must be in liters. (Show work below) M of HC,H,O2 in diluted vinegar sample Give the molarity of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in 4. the titration. O-02754M of HC,H,O2 in undiluted or original vinegar CALCULATIONS FOR MASS PERCENT OF ACETIC ACID IN VINEGAR 5. Convert the moles of acetic acid (HC,H,0,) in the diluted vinegar sample (previously calculated in question 2) to grams of HC,H,O,. Show your work. (You will need to use the molar mass of acetic acid for this calculation.) g of HC,H;O2 3. Using the equation below, calculate the mass percent of acetic acid in the diluted vinegar sample. The density of the vinegar is 1.00 g/mL so you can assume that the mass of vinegar in grams is essentially equal to the volume of vinegar in mL. Show your work below. mass of acetic acid mass of vinegar sample Percent by mass = x 100 % by mass of HC,H,O2 in diluted vinegar sample 7. Give the percent by mass of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in the titration. % by mass of HC,H;O2 in undiluted or original vinegar
3. Calculate the molarity of acetic acid in the diluted vinegar sample using the calculated moles of HC,H;0, in the 15.00 mL diluted vinegar sample. Remember to find molarity the volume must be in liters. (Show work below) M of HC,H,O2 in diluted vinegar sample Give the molarity of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in 4. the titration. O-02754M of HC,H,O2 in undiluted or original vinegar CALCULATIONS FOR MASS PERCENT OF ACETIC ACID IN VINEGAR 5. Convert the moles of acetic acid (HC,H,0,) in the diluted vinegar sample (previously calculated in question 2) to grams of HC,H,O,. Show your work. (You will need to use the molar mass of acetic acid for this calculation.) g of HC,H;O2 3. Using the equation below, calculate the mass percent of acetic acid in the diluted vinegar sample. The density of the vinegar is 1.00 g/mL so you can assume that the mass of vinegar in grams is essentially equal to the volume of vinegar in mL. Show your work below. mass of acetic acid mass of vinegar sample Percent by mass = x 100 % by mass of HC,H,O2 in diluted vinegar sample 7. Give the percent by mass of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in the titration. % by mass of HC,H;O2 in undiluted or original vinegar
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:EXPERIMENT K Acid-Base Titration: How Much Acid Is In Vinegar?
Discussion
The label on the bottle of commercial vinegar states that it contains 5.0% acetic acid.
According to your calculations, has the manufacture truthfully reported the percent of
acetic acid in vinegar? Support your answer with data.
1.
2. A grocery store sells vinegar in 1-L bottles. Based on your answer to question 4 on the
previous page.
how many moles of acetic acid are in a 1-L bottle of vinegar?
a.
60.9
if 10.00 mL of
b. how many grams of acetic acid are in a 1-L bottle of vinegar? 6.0 9
3. Would the calculated molarity of acetic acid in vinegar be
diluted vinegar had been used in place of the 15.00 mL sample. Explain your answer.
a.
the same
D, higher
С.
lower
4. If you over-titrate, a significant error will occur in your calculations. Determine how
each of the following values would be affected if you over-titrate? Circle the cor-
rect response.
The volume of NaOH recorded to reach the equivalence point would be (too
high or too low).
a.
b. The calculated moles of NAOH used to reach the equivalence point would be (too
(high or too low).
C.
The calculated moles of acetic acid neutralized by the NAOH would be (too
high or too low).
d. The calculated molarity of acetic acid of the vinegar sample would be (too
high or too low).

Transcribed Image Text:MENT K Acid-Base Titration: How Much Acid Is In Vinegar?
3. Calculate the molarity of acetic acid in the diluted vinegar sample using the calculated
moles of HC,H,O, in the 15.00 mL diluted vinegar sample. Remember to find molarity
the volume must be in liters. (Show work below)
M of HC,H3O2 in diluted vinegar sample
4.
Give the molarity of acetic acid in the vinegar before it was diluted. The original vinegar
from the store is 10 times more concentrated than the diluted vinegar sample used in
the titration.
O-02154 M of HC,H,O, in undiluted or original vinegar
CALCULATIONS FOR MASS PERCENT OF ACETIC ACID IN VINEGAR
5. Convert the moles of acetic acid (HC,H,O2) in the diluted vinegar sample (previously
calculated in question 2) to grams of HC,H,O2. Show your work. (You will need to use
the molar mass of acetic acid for this calculation.)
g of HC,H;O2
6. Using the equation below, calculate the mass percent of acetic acid in the diluted
vinegar sample. The density of the vinegar is 1.00 g/mL so you can assume that the
mass of vinegar in grams is essentially equal to the volume of vinegar in mL. Show
your work below.
mass of acetic acid
Percent by mass =
x 100
mass of vinegar sample
% by mass of HC,H,O2 in diluted vinegar sample
7. Give the percent by mass of acetic acid in the vinegar before it was diluted. The original
vinegar from the store is 10 times more concentrated than the diluted vinegar sample
used in the titration.
% by mass of HC,H,O, in undiluted or original vinegar
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