Dry chemicals Sometimes you will need to make a solution of a specific molarity (M) from dry chemicals that need to be weighed. Recall that M units g/mole. You can use the equation below to determine the mass of the chemical you need to make the solution. = moles / L and the molecular weight of a chemical is in the Mass (g) = Molarity (M) * Volume (L) * Molecular Weight (g/mole) To get the units to cancel out, you need to use the units in the equation above. You can obtain t molecular weights from the bottle in which the chemical is stored (or by using a periodic table Example: Make 300 mL of 100 mM glycine 100 mM =0.1 M= 0.1 moles/L 300 mL = 0.3 L The molecular weight of glycine 75.07 g/ mol. %3D 0.1 moles/L 0.3 L 75.07 g/mole = 2.25 g of glycine %3D How much of the dry chemical is needed to make the following solutions? Your solvent will always be deionized water (DI H2O). Show your work. a. Make 25 mL of a 0.05 M glycine solution. The molecular weight of glycine is 75.07 g / r Make 500 mL of a 10 mM NaCl solution.
Dry chemicals Sometimes you will need to make a solution of a specific molarity (M) from dry chemicals that need to be weighed. Recall that M units g/mole. You can use the equation below to determine the mass of the chemical you need to make the solution. = moles / L and the molecular weight of a chemical is in the Mass (g) = Molarity (M) * Volume (L) * Molecular Weight (g/mole) To get the units to cancel out, you need to use the units in the equation above. You can obtain t molecular weights from the bottle in which the chemical is stored (or by using a periodic table Example: Make 300 mL of 100 mM glycine 100 mM =0.1 M= 0.1 moles/L 300 mL = 0.3 L The molecular weight of glycine 75.07 g/ mol. %3D 0.1 moles/L 0.3 L 75.07 g/mole = 2.25 g of glycine %3D How much of the dry chemical is needed to make the following solutions? Your solvent will always be deionized water (DI H2O). Show your work. a. Make 25 mL of a 0.05 M glycine solution. The molecular weight of glycine is 75.07 g / r Make 500 mL of a 10 mM NaCl solution.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Dry chemicals
Sometimes you will need to make a solution of a specific molarity (M) from dry chemicals that
need to be weighed. Recall that M = moles /L and the molecular weight of a chemical is in the
units g/ mole. You can use the equation below to determine the mass of the chemical you need
to make the solution.
Mass (g) = Molarity (M) * Volume (L) * Molecular Weight (g/mole)
To get the units to cancel out, you need to use the units in the equation above. You can obtain the
molecular weights from the bottle in which the chemical is stored (or by using a periodic table).
Example: Make 300 mL of 100 mM glycine
100 mM = 0.1 M= 0.1 moles/L
300 mL = 0.3 L
The molecular weight of glycine 75.07 g/ mol.
0.1 moles/L * 0.3 L * 75.07 g/mole = 2.25 g of glycine
How much of the dry chemical is needed to make the following solutions? Your solvent will
always be deionized water (DI H2O). Show your work.
a. Make 25 mL of a 0.05 M glycine solution. The molecular weight of glycine is 75.07 g/ mol.
b. Make 500 mL of a 10 mM NaCl solution.
c. Make 1 L of a 0.5 M K2SO4 solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83b1968a-5e2b-4d03-895e-6da4f3344c3b%2Fbc86f916-51ae-40ec-9b77-9cee3087c2c9%2Fu635qor_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Dry chemicals
Sometimes you will need to make a solution of a specific molarity (M) from dry chemicals that
need to be weighed. Recall that M = moles /L and the molecular weight of a chemical is in the
units g/ mole. You can use the equation below to determine the mass of the chemical you need
to make the solution.
Mass (g) = Molarity (M) * Volume (L) * Molecular Weight (g/mole)
To get the units to cancel out, you need to use the units in the equation above. You can obtain the
molecular weights from the bottle in which the chemical is stored (or by using a periodic table).
Example: Make 300 mL of 100 mM glycine
100 mM = 0.1 M= 0.1 moles/L
300 mL = 0.3 L
The molecular weight of glycine 75.07 g/ mol.
0.1 moles/L * 0.3 L * 75.07 g/mole = 2.25 g of glycine
How much of the dry chemical is needed to make the following solutions? Your solvent will
always be deionized water (DI H2O). Show your work.
a. Make 25 mL of a 0.05 M glycine solution. The molecular weight of glycine is 75.07 g/ mol.
b. Make 500 mL of a 10 mM NaCl solution.
c. Make 1 L of a 0.5 M K2SO4 solution.
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