3. Determine the concentration of a diluted solution of sodium chloride that was prepared by diluting 10.0 mL of a 4.5 M solution of sodium chloride to 250.0 mL.
3. Determine the concentration of a diluted solution of sodium chloride that was prepared by diluting 10.0 mL of a 4.5 M solution of sodium chloride to 250.0 mL.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
Determine the concentration of a diluted solution of sodium chloride that was prepared by diluting 10.0 mL of a 4.5 M solution of sodium chloride to 250.0 mL.
**Explanation:**
To solve this problem, we can use the dilution formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the initial concentration (4.5 M).
- \( V_1 \) is the initial volume (10.0 mL).
- \( C_2 \) is the final concentration (unknown).
- \( V_2 \) is the final volume (250.0 mL).
Plugging the known values into the equation:
\[ (4.5 \, \text{M})(10.0 \, \text{mL}) = C_2(250.0 \, \text{mL}) \]
Solving for \( C_2 \):
\[ C_2 = \frac{(4.5 \, \text{M})(10.0 \, \text{mL})}{250.0 \, \text{mL}} \]
\[ C_2 = \frac{45.0}{250.0} \]
\[ C_2 = 0.18 \, \text{M} \]
Thus, the concentration of the diluted sodium chloride solution is 0.18 M.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F04d91ec5-5dc8-475a-a219-706d13e893d1%2F40359bd2-8945-4ef1-accc-8639cf3e5c87%2Fdcb7c72_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Determine the concentration of a diluted solution of sodium chloride that was prepared by diluting 10.0 mL of a 4.5 M solution of sodium chloride to 250.0 mL.
**Explanation:**
To solve this problem, we can use the dilution formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the initial concentration (4.5 M).
- \( V_1 \) is the initial volume (10.0 mL).
- \( C_2 \) is the final concentration (unknown).
- \( V_2 \) is the final volume (250.0 mL).
Plugging the known values into the equation:
\[ (4.5 \, \text{M})(10.0 \, \text{mL}) = C_2(250.0 \, \text{mL}) \]
Solving for \( C_2 \):
\[ C_2 = \frac{(4.5 \, \text{M})(10.0 \, \text{mL})}{250.0 \, \text{mL}} \]
\[ C_2 = \frac{45.0}{250.0} \]
\[ C_2 = 0.18 \, \text{M} \]
Thus, the concentration of the diluted sodium chloride solution is 0.18 M.
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