Part I: Reactions in Aqueous Solutions In General Chemistry 2 there are some new ideas that depend on your understanding of molarity, dilutions, and solutions stoichiometry. This course is largely a course in aqueous solution chemistry and therefore molarity is probably the most important unit we will use all semester. This part of the workshop is designed to help you review molarity (see Topic 18 from Chem102). Molarity (M) is the number of moles of a substance (solute) per 1 L of solution: M = mol/L and M = n/V, where n is the number of moles of solute and V is the volume of solution. You also need to know how to use the dilution formula: M₁V1 = M₂V2. Before you write down your answers to the questions below please take a moment to discuss them with your group. You should be able to solve these types of questions "in your sleep"! Ⓒ 1. A student dissolved 0.75 g of solid calcium phosphate in enough acidified water to make 220 mL of solution (this salt is soluble in acidic solutions). What is the molarity of this calcium phosphate aqueous solution? a. What is the chemical formula for calcium phosphate? b. Is calcium phosphate an ionic compound or a covalent compound? Explain your answer. c. How many moles of calcium phosphate are there in 0.75 g of calcium phosphate? What is the molarity of the produced solution? One last question about calcium phosphate: When 1 formula unit of calcium phosphate is added to water, how many ions are formed? Remember that ions are charged and so you MUST indicate the correct charge on each ion to receive credit for this question.
Part I: Reactions in Aqueous Solutions In General Chemistry 2 there are some new ideas that depend on your understanding of molarity, dilutions, and solutions stoichiometry. This course is largely a course in aqueous solution chemistry and therefore molarity is probably the most important unit we will use all semester. This part of the workshop is designed to help you review molarity (see Topic 18 from Chem102). Molarity (M) is the number of moles of a substance (solute) per 1 L of solution: M = mol/L and M = n/V, where n is the number of moles of solute and V is the volume of solution. You also need to know how to use the dilution formula: M₁V1 = M₂V2. Before you write down your answers to the questions below please take a moment to discuss them with your group. You should be able to solve these types of questions "in your sleep"! Ⓒ 1. A student dissolved 0.75 g of solid calcium phosphate in enough acidified water to make 220 mL of solution (this salt is soluble in acidic solutions). What is the molarity of this calcium phosphate aqueous solution? a. What is the chemical formula for calcium phosphate? b. Is calcium phosphate an ionic compound or a covalent compound? Explain your answer. c. How many moles of calcium phosphate are there in 0.75 g of calcium phosphate? What is the molarity of the produced solution? One last question about calcium phosphate: When 1 formula unit of calcium phosphate is added to water, how many ions are formed? Remember that ions are charged and so you MUST indicate the correct charge on each ion to receive credit for this question.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How can we answer these questions on solution stoichiometry and equilibrium?
Transcribed Image Text:Part I: Reactions in Aqueous Solutions
In General Chemistry 2 there are some new ideas that depend on your understanding of
molarity, dilutions, and solutions stoichiometry. This course is largely a course in aqueous
solution chemistry and therefore molarity is probably the most important unit we will use all
semester. This part of the workshop is designed to help you review molarity (see Topic 18 from
Chem102).
Molarity (M) is the number of moles of a substance (solute) per 1 L of solution: M = mol/L and
M = n/V, where n is the number of moles of solute and V is the volume of solution. You also need
to know how to use the dilution formula: M₁V1 = M₂V2.
Before you write down your answers to the questions below please take a moment to discuss
them with your group. You should be able to solve these types of questions "in your sleep"! Ⓒ
1. A student dissolved 0.75 g of solid calcium phosphate in enough acidified water to make 220
mL of solution (this salt is soluble in acidic solutions). What is the molarity of this calcium
phosphate aqueous solution?
a. What is the chemical formula for calcium phosphate?
b. Is calcium phosphate an ionic compound or a covalent compound? Explain your answer.
c. How many moles of calcium phosphate are there in 0.75 g of calcium phosphate? What is
the molarity of the produced solution?
problem famounts
One last question about calcium phosphate: When 1 formula unit of calcium phosphate is
added to water, how many ions are formed? Remember that ions are charged and so you
MUST indicate the correct charge on each ion to receive credit for this question.
2
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