1. Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of1010 g/L. If vinegar is 0.80 M acetic acid, what is the % by mass concentration of acetic acid invinegar?2. How would each of the following errors affect the experimental value of your molarity of acetic?Would your Molarity value be too high, too low, or unaffected? Explain your answer.a. if you titrated your acid sample to a bright pink rather than faint pink endpoint?b. if your "acetic acid" buret was still wet inside with deionized water when you filled it with aceticacid?c.if you recorded the final volume of NaOH as "39.88 mL" instead of "38.88 mL"?

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1. Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of 1010 g/L. If vinegar is 0.80 M acetic acid, what is the % by mass concentration of acetic acid in vinegar?

1. Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of 1010 g/L. If vinegar is 0.80 M acetic acid, what is the % by mass concentration of acetic acid in vinegar?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

1. Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of
1010 g/L. If vinegar is 0.80 M acetic acid, what is the % by mass concentration of acetic acid in
vinegar?
2. How would each of the following errors affect the experimental value of your molarity of acetic?
Would your Molarity value be too high, too low, or unaffected? Explain your answer.
a. if you titrated your acid sample to a bright pink rather than faint pink endpoint?
b. if your "acetic acid" buret was still wet inside with deionized water when you filled it with acetic
acid?
c.if you recorded the final volume of NaOH as "39.88 mL" instead of "38.88 mL"?

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