A 100.0 ml. solution containing 0.794 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.228 M KOH. Calculate the pH of the solution after the addition of 60.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H, M, HM", and M2-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. (M) (HM"] = M

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A 100.0 mL solution containing 0.794 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.228 M KOH. Calculate the pH
of the solution after the addition of 60.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27.
pH =
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid
are abbreviated as H, M, HM", and M2-, which represent the fully protonated, intermediate, and fully deprotonated
forms, respectively.
(M²-] =
%3D
(HM"| =
%3D
Transcribed Image Text:A 100.0 mL solution containing 0.794 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.228 M KOH. Calculate the pH of the solution after the addition of 60.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H, M, HM", and M2-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. (M²-] = %3D (HM"| = %3D
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