A hydrocarbon (D) is 88.23 % carbon by mass. The empirical formula of this compound is: (Atomic mass: Carbon = 12; Hydrogen = 1) %3D Select one: a. C2H5 b. C3H5 c. CGH8 d. CH3 Chlorobenzene is formed from benzene via: Select one: a. the free radical reaction with chlorine. b. a hydrohalogenation reaction. c. an electrophilic substitution reaction. d. an electrophilic addition reaction.

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d. Chlorine gas is one of the products of the propagation phase.

A hydrocarbon (D) is 88.23 % carbon by mass. The empirical formula of this compound is:
(Atomic mass: Carbon = 12; Hydrogen = 1)
Select one:
a. C2H5
b. C3H5
c. C5H3
d. CH3
С.
Chlorobenzene is formed from benzene via:
Select one:
a. the free radical reaction with chlorine.
b. a hydrohalogenation reaction.
c. an electrophilic substitution reaction.
d. an electrophilic addition reaction.
CH3
H.
H.
A
The preparation of compound A shown above could involve the:
Select one:
a. base-catalysed dehydrohalogenation of an alkyl halide.
b. reaction of hydrogen with nickel catalyst with an alkyne.
c. dehalogenation of an alkyl halide.
d. free radical halogenation of an alkane.
In the monochlorination of the compound shown below,
H
CH3
H -C
C
-CH3
H
CH3
Select one:
a. the radical carbon formed is a secondary radical.
b. the radical carbon formed is a primary radical.
c. the termination phase involves the formation of two radicals.
Transcribed Image Text:A hydrocarbon (D) is 88.23 % carbon by mass. The empirical formula of this compound is: (Atomic mass: Carbon = 12; Hydrogen = 1) Select one: a. C2H5 b. C3H5 c. C5H3 d. CH3 С. Chlorobenzene is formed from benzene via: Select one: a. the free radical reaction with chlorine. b. a hydrohalogenation reaction. c. an electrophilic substitution reaction. d. an electrophilic addition reaction. CH3 H. H. A The preparation of compound A shown above could involve the: Select one: a. base-catalysed dehydrohalogenation of an alkyl halide. b. reaction of hydrogen with nickel catalyst with an alkyne. c. dehalogenation of an alkyl halide. d. free radical halogenation of an alkane. In the monochlorination of the compound shown below, H CH3 H -C C -CH3 H CH3 Select one: a. the radical carbon formed is a secondary radical. b. the radical carbon formed is a primary radical. c. the termination phase involves the formation of two radicals.
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