The halogenation reaction above will always produce _______ isomers. a. cis- b. trans- c. both cis- and trans- d. neither cis- nor trans-

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The halogenation reaction above will always produce _______ isomers.

a. cis-
b. trans-
c. both cis- and trans-
d. neither cis- nor trans-
**Halogenation Reaction Example**

**Chemical Reaction:**

- **Reactants:** 
  - Ethene (\( \text{H}_2C=CH_2 \))
  - Bromine (\( \text{Br}_2 \))

- **Products:** 
  - 1,2-Dibromoethane (\( \text{H}_2CBr-CHBr\))

**Reaction Description:**
In this halogenation reaction, ethene reacts with bromine to form 1,2-dibromoethane. This involves the addition of bromine across the double bond in ethene.

**Question 23:**
The halogenation reaction above will always produce:

- a. cis-
- b. trans-
- c. both cis- and trans-
- d. neither cis- nor trans-

**Explanation:**
The diagram illustrates ethene reacting with bromine to form a saturated compound, eliminating the possibility of cis-trans isomerism, which occurs in alkenes with different groups attached to the carbon atoms involved in a double bond. In this case, the product is saturated, meaning options (a) and (b) do not apply since 1,2-dibromoethane lacks double bonds and the conditions allowing for cis-trans isomerism.
Transcribed Image Text:**Halogenation Reaction Example** **Chemical Reaction:** - **Reactants:** - Ethene (\( \text{H}_2C=CH_2 \)) - Bromine (\( \text{Br}_2 \)) - **Products:** - 1,2-Dibromoethane (\( \text{H}_2CBr-CHBr\)) **Reaction Description:** In this halogenation reaction, ethene reacts with bromine to form 1,2-dibromoethane. This involves the addition of bromine across the double bond in ethene. **Question 23:** The halogenation reaction above will always produce: - a. cis- - b. trans- - c. both cis- and trans- - d. neither cis- nor trans- **Explanation:** The diagram illustrates ethene reacting with bromine to form a saturated compound, eliminating the possibility of cis-trans isomerism, which occurs in alkenes with different groups attached to the carbon atoms involved in a double bond. In this case, the product is saturated, meaning options (a) and (b) do not apply since 1,2-dibromoethane lacks double bonds and the conditions allowing for cis-trans isomerism.
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