A particular balloon is designed by its manufacturer to be in- flated to a volume of no more than 2.5 L. If the balloon is filled with 2.0 L helium at sea level, is released, and rises to an alti- tude at which the atmospheric pressure is only 500. mm Hg, will the balloon burst? (Assume temperature is constant.)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question

help with this problem? explain why the ballon will burst.

### Problem Statement:

A particular balloon is designed by its manufacturer to be inflated to a volume of no more than 2.5 L. If the balloon is filled with 2.0 L helium at sea level, is released, and rises to an altitude at which the atmospheric pressure is only 500. mm Hg, will the balloon burst? (Assume temperature is constant.)

### Detailed Explanation:

This problem involves understanding the relationship between pressure and volume for a gas, where temperature is assumed to be constant. We use Boyle's Law for this purpose. Boyle's Law states that for a fixed amount of gas at a constant temperature, the volume (V) and pressure (P) of the gas are inversely proportional, which can be mathematically expressed as:

\[ P_1 V_1 = P_2 V_2 \]

#### Given Data:
- The balloon's maximum volume: \( V_{max} = 2.5 \, \text{L} \)
- Initial volume of helium at sea level: \( V_1 = 2.0 \, \text{L} \)
- Pressure at sea level: \( P_1 = 760 \, \text{mm Hg} \) (standard atmospheric pressure)
- Pressure at altitude: \( P_2 = 500 \, \text{mm Hg} \)

#### Problem Solving:
We need to determine the final volume of the helium in the balloon at the lower pressure of 500 mm Hg and check if it exceeds the maximum allowed volume.

Using Boyle's Law:

\[ P_1 V_1 = P_2 V_2 \]

We can rearrange this equation to solve for \( V_2 \):

\[ V_2 = \frac{P_1 V_1}{P_2} \]

Substitute the known values into the equation:

\[ V_2 = \frac{760 \, \text{mm Hg} \times 2.0 \, \text{L}}{500 \, \text{mm Hg}} \]

\[ V_2 = \frac{1520 \, \text{L mm Hg}}{500 \, \text{mm Hg}} \]

\[ V_2 = 3.04 \, \text{L} \]

#### Conclusion:
Since the final volume of the helium when the balloon rises to an altitude with pressure of 500 mm Hg is 3.04
Transcribed Image Text:### Problem Statement: A particular balloon is designed by its manufacturer to be inflated to a volume of no more than 2.5 L. If the balloon is filled with 2.0 L helium at sea level, is released, and rises to an altitude at which the atmospheric pressure is only 500. mm Hg, will the balloon burst? (Assume temperature is constant.) ### Detailed Explanation: This problem involves understanding the relationship between pressure and volume for a gas, where temperature is assumed to be constant. We use Boyle's Law for this purpose. Boyle's Law states that for a fixed amount of gas at a constant temperature, the volume (V) and pressure (P) of the gas are inversely proportional, which can be mathematically expressed as: \[ P_1 V_1 = P_2 V_2 \] #### Given Data: - The balloon's maximum volume: \( V_{max} = 2.5 \, \text{L} \) - Initial volume of helium at sea level: \( V_1 = 2.0 \, \text{L} \) - Pressure at sea level: \( P_1 = 760 \, \text{mm Hg} \) (standard atmospheric pressure) - Pressure at altitude: \( P_2 = 500 \, \text{mm Hg} \) #### Problem Solving: We need to determine the final volume of the helium in the balloon at the lower pressure of 500 mm Hg and check if it exceeds the maximum allowed volume. Using Boyle's Law: \[ P_1 V_1 = P_2 V_2 \] We can rearrange this equation to solve for \( V_2 \): \[ V_2 = \frac{P_1 V_1}{P_2} \] Substitute the known values into the equation: \[ V_2 = \frac{760 \, \text{mm Hg} \times 2.0 \, \text{L}}{500 \, \text{mm Hg}} \] \[ V_2 = \frac{1520 \, \text{L mm Hg}}{500 \, \text{mm Hg}} \] \[ V_2 = 3.04 \, \text{L} \] #### Conclusion: Since the final volume of the helium when the balloon rises to an altitude with pressure of 500 mm Hg is 3.04
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Ideal and Real Gases
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY