At 189 K, a sample of gas has a volume of 32.0 cm³. You need to determine the volume occupied by the gas once it is heated to 242 K.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve EXACTLY like the example.

Gas Laws
Charles' Law
331-273=C
1. Identify givens and the unknown.
2. Convert all temperatures to Kelvin.
3. Rearrange the equation if you'd like.
4. Substitute values into the equation.
Solve for the unknown.
5.
6. Check your answer against theory.
58 C
A sample of gas has a volume of 852 mL at 25 °C.
va
You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL.
Prediction using theory: The final temperature will be greater than 25 °C.
= 852 ml
V1
V2 =945 ml
V₁ = V₂
1
Т1 Т2
T1 = 25 C+273=298 k
T2 = 331 K
Vi*T2=V2*T1
VT
VI
T2=945 ml 298 k
852 ml
T2=331 K
Transcribed Image Text:Gas Laws Charles' Law 331-273=C 1. Identify givens and the unknown. 2. Convert all temperatures to Kelvin. 3. Rearrange the equation if you'd like. 4. Substitute values into the equation. Solve for the unknown. 5. 6. Check your answer against theory. 58 C A sample of gas has a volume of 852 mL at 25 °C. va You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL. Prediction using theory: The final temperature will be greater than 25 °C. = 852 ml V1 V2 =945 ml V₁ = V₂ 1 Т1 Т2 T1 = 25 C+273=298 k T2 = 331 K Vi*T2=V2*T1 VT VI T2=945 ml 298 k 852 ml T2=331 K
REFER TO THESE WORKED EXAMPLES AS YOU ATTEMPT TO SOLVE YOUR PROBLEM:
A sample of gas has a volume of 852 mL at 25 °C.
You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL.
#1
V1 = 852 mL
V2 = 945 mL
T1 = 25 C (+ 273 = 298 K)
T2 = ?
1.
Identify givens and the unknown.
2. Convert all temperatures to Kelvin.
3. Rearrange the equation if you'd like.
4. Substitute values into the equation.
Solve for the unknown.
5.
6. Check your answer against theory.
T2 converted back to Celsius:
330 K -273 K = 57 C
V₁ = V₂
T₁ T₂
At 189 K, a sample of gas has a volume of 32.0 cm³.
You need to determine the volume occupied by
the gas once it is heated to 242 K.
ANSWER CHECK LINK:
P
852 mL
945 mL
298 K
T2
T2*852 mL = 298 K * 945 mL
852 mL
852 mi
T2 = 330 K
Transcribed Image Text:REFER TO THESE WORKED EXAMPLES AS YOU ATTEMPT TO SOLVE YOUR PROBLEM: A sample of gas has a volume of 852 mL at 25 °C. You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL. #1 V1 = 852 mL V2 = 945 mL T1 = 25 C (+ 273 = 298 K) T2 = ? 1. Identify givens and the unknown. 2. Convert all temperatures to Kelvin. 3. Rearrange the equation if you'd like. 4. Substitute values into the equation. Solve for the unknown. 5. 6. Check your answer against theory. T2 converted back to Celsius: 330 K -273 K = 57 C V₁ = V₂ T₁ T₂ At 189 K, a sample of gas has a volume of 32.0 cm³. You need to determine the volume occupied by the gas once it is heated to 242 K. ANSWER CHECK LINK: P 852 mL 945 mL 298 K T2 T2*852 mL = 298 K * 945 mL 852 mL 852 mi T2 = 330 K
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