Ideal and Real Gases
Ideal gases obey conditions of the general gas laws under all states of pressure and temperature. Ideal gases are also named perfect gases. The attributes of ideal gases are as follows,
Gas Laws
Gas laws describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. The very first observations about the physical properties of gases was made by Robert Boyle in 1662. Later discoveries were made by Charles, Gay-Lussac, Avogadro, and others. Eventually, these observations were combined to produce the ideal gas law.
Gaseous State
It is well known that matter exists in different forms in our surroundings. There are five known states of matter, such as solids, gases, liquids, plasma and Bose-Einstein condensate. The last two are known newly in the recent days. Thus, the detailed forms of matter studied are solids, gases and liquids. The best example of a substance that is present in different states is water. It is solid ice, gaseous vapor or steam and liquid water depending on the temperature and pressure conditions. This is due to the difference in the intermolecular forces and distances. The occurrence of three different phases is due to the difference in the two major forces, the force which tends to tightly hold molecules i.e., forces of attraction and the disruptive forces obtained from the thermal energy of molecules.
Solve EXACTLY like the example.
![Gas Laws
Charles' Law
331-273=C
1. Identify givens and the unknown.
2. Convert all temperatures to Kelvin.
3. Rearrange the equation if you'd like.
4. Substitute values into the equation.
Solve for the unknown.
5.
6. Check your answer against theory.
58 C
A sample of gas has a volume of 852 mL at 25 °C.
va
You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL.
Prediction using theory: The final temperature will be greater than 25 °C.
= 852 ml
V1
V2 =945 ml
V₁ = V₂
1
Т1 Т2
T1 = 25 C+273=298 k
T2 = 331 K
Vi*T2=V2*T1
VT
VI
T2=945 ml 298 k
852 ml
T2=331 K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb36515eb-11f6-46a8-971a-a28c1e96e258%2F28c11334-c4ff-469e-a65d-514c33924e5e%2Fdreegkb_processed.png&w=3840&q=75)
![REFER TO THESE WORKED EXAMPLES AS YOU ATTEMPT TO SOLVE YOUR PROBLEM:
A sample of gas has a volume of 852 mL at 25 °C.
You need to determine the Celsius temperature necessary for the gas to have a volume of 945 mL.
#1
V1 = 852 mL
V2 = 945 mL
T1 = 25 C (+ 273 = 298 K)
T2 = ?
1.
Identify givens and the unknown.
2. Convert all temperatures to Kelvin.
3. Rearrange the equation if you'd like.
4. Substitute values into the equation.
Solve for the unknown.
5.
6. Check your answer against theory.
T2 converted back to Celsius:
330 K -273 K = 57 C
V₁ = V₂
T₁ T₂
At 189 K, a sample of gas has a volume of 32.0 cm³.
You need to determine the volume occupied by
the gas once it is heated to 242 K.
ANSWER CHECK LINK:
P
852 mL
945 mL
298 K
T2
T2*852 mL = 298 K * 945 mL
852 mL
852 mi
T2 = 330 K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb36515eb-11f6-46a8-971a-a28c1e96e258%2F28c11334-c4ff-469e-a65d-514c33924e5e%2Ffspogs_processed.png&w=3840&q=75)
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