A food delivery service claims that it delivers orders to customers in 39.6 minutes or less, on average. However, many people report that their recent orders have taken much longer to arrive. A secret shopping firm would like to test the company's claim. The firm collected data from 243 randomly selected orders and found that the average delivery time was 39.86 minutes with a standard deviation of 5.66 minutes. Using a significance level of 0.5%, test the hypothesis that the average delivery time from this food delivery service is greater than 39.6 minutes. Use the critical value method.

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### Hypothesis Testing for Average Food Delivery Time

This section guides you through the process of hypothesis testing to determine if the average food delivery time is as advertised.

#### Step-by-Step Instructions

**1. Determine the critical value(s) for this hypothesis test.**

- The standard normal (Z) distribution should be used.
- Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list. 

**[Input Box]**

**2. Determine the test statistic.**

- Round the solution to four decimal places.

**[Input Box]**

**3. Determine the appropriate conclusion for this hypothesis test.**

Choose one of the following options:

a) The sample data provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 39.6 minutes or less and thus we conclude that average food delivery time is likely greater than 39.6 minutes.

b) The sample data provide sufficient evidence to reject the alternative hypothesis that the average food delivery time is greater than 39.6 minutes and thus we conclude that the average food delivery time from this company is 39.6 minutes or less, as advertised.

c) The sample data do not provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 39.6 minutes or less and thus we conclude that average food delivery time is likely 39.6 minutes or less, as advertised.

d) The sample data do not provide sufficient evidence to reject the alternative hypothesis that the average food delivery time is greater than 39.6 minutes and thus we conclude that the average food delivery time from this company is likely greater than 39.6 minutes.

**Answer Choices:**

- ○ Option a)
- ○ Option b)
- ○ Option c)
- ○ Option d)

#### Explanation of Graphs and Diagrams
There are no graphs or diagrams in this portion of the exercise; it focuses solely on the textual and numeric inputs for hypothesis testing. However, providing any additional graphical representation would typically involve illustrating the normal distribution curve, marking the critical values, and shading the rejection regions on the curve.

**Footer Note:**
Weather: 76°F, Mostly clear
Transcribed Image Text:### Hypothesis Testing for Average Food Delivery Time This section guides you through the process of hypothesis testing to determine if the average food delivery time is as advertised. #### Step-by-Step Instructions **1. Determine the critical value(s) for this hypothesis test.** - The standard normal (Z) distribution should be used. - Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list. **[Input Box]** **2. Determine the test statistic.** - Round the solution to four decimal places. **[Input Box]** **3. Determine the appropriate conclusion for this hypothesis test.** Choose one of the following options: a) The sample data provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 39.6 minutes or less and thus we conclude that average food delivery time is likely greater than 39.6 minutes. b) The sample data provide sufficient evidence to reject the alternative hypothesis that the average food delivery time is greater than 39.6 minutes and thus we conclude that the average food delivery time from this company is 39.6 minutes or less, as advertised. c) The sample data do not provide sufficient evidence to reject the null hypothesis that the average food delivery time from this company is 39.6 minutes or less and thus we conclude that average food delivery time is likely 39.6 minutes or less, as advertised. d) The sample data do not provide sufficient evidence to reject the alternative hypothesis that the average food delivery time is greater than 39.6 minutes and thus we conclude that the average food delivery time from this company is likely greater than 39.6 minutes. **Answer Choices:** - ○ Option a) - ○ Option b) - ○ Option c) - ○ Option d) #### Explanation of Graphs and Diagrams There are no graphs or diagrams in this portion of the exercise; it focuses solely on the textual and numeric inputs for hypothesis testing. However, providing any additional graphical representation would typically involve illustrating the normal distribution curve, marking the critical values, and shading the rejection regions on the curve. **Footer Note:** Weather: 76°F, Mostly clear
### Hypothesis Testing for Delivery Time Claims

**Problem Statement:**
A food delivery service claims that it delivers orders to customers in 39.6 minutes or less, on average. However, many people report that their recent orders have taken much longer to arrive. A secret shopping firm would like to test the company's claim. The firm collected data from 243 randomly selected orders and found that the average delivery time was 39.86 minutes with a standard deviation of 5.66 minutes.

Using a significance level of 0.5%, test the hypothesis that the average delivery time from this food delivery service is greater than 39.6 minutes. Use the critical value method.

**State the Null and Alternative Hypotheses:**
- \( H_0 \): ?
- \( H_1 \): ?

**Determine if this test is left-tailed, right-tailed, or two-tailed:**
- Left-tailed
- Two-tailed
- Right-tailed

**Choose the distribution to use:**
- The Student's t distribution should be used
- The standard normal (z) distribution should be used

**Determine the critical value(s) for this hypothesis test.** Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list.

---

**Detailed Explanation**

**Formulating Hypotheses:**
1. The null hypothesis (\( H_0 \)) represents the claim to be tested and is usually a statement of no effect or no difference. Here, it will test the company's claim.
2. The alternative hypothesis (\( H_1 \)) represents a statement that disagrees with the null hypothesis and is what you set out to prove.

For this scenario:
- \( H_0 \): \(\mu \leq 39.6\)
- \( H_1 \): \(\mu > 39.6\)

**Tail of the Test:**
Since the firm suspects that the actual delivery time is greater than the claimed 39.6 minutes, this is a right-tailed test.

**Choosing the Distribution:**
Given the large sample size (n = 243), the standard normal (z) distribution will be appropriate for this test.

**Critical Value Determination:**
To find the critical value for a right-tailed test at a 0.5% significance level, you look up the z-value corresponding to the cumulative probability of 1
Transcribed Image Text:### Hypothesis Testing for Delivery Time Claims **Problem Statement:** A food delivery service claims that it delivers orders to customers in 39.6 minutes or less, on average. However, many people report that their recent orders have taken much longer to arrive. A secret shopping firm would like to test the company's claim. The firm collected data from 243 randomly selected orders and found that the average delivery time was 39.86 minutes with a standard deviation of 5.66 minutes. Using a significance level of 0.5%, test the hypothesis that the average delivery time from this food delivery service is greater than 39.6 minutes. Use the critical value method. **State the Null and Alternative Hypotheses:** - \( H_0 \): ? - \( H_1 \): ? **Determine if this test is left-tailed, right-tailed, or two-tailed:** - Left-tailed - Two-tailed - Right-tailed **Choose the distribution to use:** - The Student's t distribution should be used - The standard normal (z) distribution should be used **Determine the critical value(s) for this hypothesis test.** Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list. --- **Detailed Explanation** **Formulating Hypotheses:** 1. The null hypothesis (\( H_0 \)) represents the claim to be tested and is usually a statement of no effect or no difference. Here, it will test the company's claim. 2. The alternative hypothesis (\( H_1 \)) represents a statement that disagrees with the null hypothesis and is what you set out to prove. For this scenario: - \( H_0 \): \(\mu \leq 39.6\) - \( H_1 \): \(\mu > 39.6\) **Tail of the Test:** Since the firm suspects that the actual delivery time is greater than the claimed 39.6 minutes, this is a right-tailed test. **Choosing the Distribution:** Given the large sample size (n = 243), the standard normal (z) distribution will be appropriate for this test. **Critical Value Determination:** To find the critical value for a right-tailed test at a 0.5% significance level, you look up the z-value corresponding to the cumulative probability of 1
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