A medical journal published the results of a study to compare the effectiveness of handwashing with soap andhandrubbing with alcohol. Health care workers who used handrubbing had a mean bacterial count of 34 per hand with astandard deviation of 65. Health care workers who used handwashing had a mean bacterial count of 67 per hand with astandard deviation of 103. In a random sample of 50 health care workers, all using the same method of cleaning theirhands, the mean bacterial count per hand, x, is less than 33. Give your opinion on whether this sample of workers usedhandrubbing with alcohol or handwashing with soap.Click the icon to view the table of normal curve areas.Since the probability of x being less than 33 isalcohol, andusedif this sample of workers used handrubbing with▼if they used handwashing with soap, it is more likely that this sample of workers

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Answered: A medical journal published the results…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A local church parish wants to raise money to add to their campus. In a sample from a previous fund raising campaign, the parish found that of the 136 people in the sample they contacted, that 70 actually contributed money. Of those that contributed money, the average contribution was $832 with a standard deviation of $266. In the recent fundraising campaign, a sample of 93 people revealed that 53 have contributed money with an average contribution of $1,162 and a standard deviation of $322. When testing (at the 5% level of significance) whether the variance of the contributions has increased in the current campaign compared to the previous campaign, what is the test statistic? (please round your answer to 2 decimal places)
A study compared the cost of restaurant meals when people pay individually versus splitting the bill as a group. In the experiment half of the people were told they would each be responsible for individual meals costs and the other half were told the cost would be split equally among the six people at the table. The 24 people paying individually had a mean cost of 37.29 Israeli shekels with a standard deviation of 12.54, while the 24 people splitting the bill had a higher mean cost of 50.92 Israeli shekels with a standard deviation of 14.33. The raw data can be found in SplitBill and both distributions are reasonably bell-shaped. Use this information to find a 95 % confidence interval for the difference in mean meal cost between these two situations. Click here for the dataset associated with this question. Round your answers to two decimal places. The 95 % confidence interval is ! to i
Statewide, the population as a whole watches 6.2 hours of TV per day. A random sample of 1017 senior citizens in the state reports watching an average of 5.9 hours per day, with a standard deviation of 0.7. is the difference significant
A bridal gown shop owner owns a store in San Francisco and a store in Redwood city. She is trying to figure out if clients tend to spend the same amount at both stores. She takes a random sample of 25 purchases from each store, and find the San Francisco store has a mean amount spent of $2500 with a standard deviation of $1500. The Redwood City store has a mean amount spent of $2000 with a standard deviation of $1000. Use a significance level of 10% to determine if the clients at the two stores spend the same amounts. State: Plan: Do: Conclude:
A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 6060 type I ovens has a mean repair cost of $77.22$⁢77.22, with a standard deviation of $22.46$⁢22.46. A sample of 6565 type II ovens has a mean repair cost of $73.73$⁢73.73, with a standard deviation of $10.62$⁢10.62. Conduct a hypothesis test of the technician's claim at the 0.10.1 level of significance. Let μ1μ1 be the true mean repair cost for type I ovens and μ2μ2 be the true mean repair cost for type II ovens. Step 2 of 4 : Compute the value of the test statistic. Round your answer to two decimal places.
In a study examining the relationship between socioeconomic status (SES) and academic achievement among high school students, the researchers collected data on 500 students from varying SES backgrounds. The SES was categorized into low, medium, and high. The academic achievement was measured using GPA scores. The following descriptive statistics were obtained: Mean GPA for low SES students: 2.8 Standard deviation of GPA for low SES students: 0.5 Mean GPA for medium SES students: 3.5 Standard deviation of GPA for medium SES students: 0.3 Mean GPA for high SES students: 4.0 Standard deviation of GPA for high SES students: 0.2 a) Calculate the coefficient of variation for each SES group and interpret the results.
A researcher collected data from Boston police officers and found that on average they spent 14.3 hours on in-service training per year with a standard deviation of 3.2. The department offers bonuses for officers in the top 10 percent on in-service training completed. Would the officer who did 22 hours of training get the bonus?
A credit score is used by credit agencies (such as mortgage companies and banks) to assess the creditworthiness of individuals. Values range from 300 to 850, with a credit score over 700 considered to be a quality credit risk. According to a survey, the mean credit score is 700.4. A credit analyst wondered whether high-income individuals (incomes in excess of $100,000 per year) had higher credit scores. He obtained a random sample of 34 high-income individuals and found the sample mean credit score to be 716.2 with a standard deviation of 81.1. Conduct the appropriate test to determine if high-income individuals have higher credit scores at the a= 0.05 level of significance. Identify the P-value. P-value = (Round to three decimal places as needed.) Help me solve this View an example Get more help . Check answer Clear all Type here to search O H Di 0 $ (?) 4:13 PM 6/18/2022 R T 6 a 96°F Sunny A
A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. What are the appropriate null and alternative hypotheses? Group of answer choices H 0: x̄ = 250 vs. H a: x̄ < 250 H 0: x̄ = 250 vs. H a: x̄ ≠ 250 H 0: x̄ = 250 vs. H a: x̄ > 250 H 0: μ = 250 vs. H a:μ < 250 H 0: μ = 250 vs. H a: μ ≠ 250 H 0: μ = 250 vs. H a: μ > 250
Fuel efficiency of Prius: Fueleconomy.gov, the official US government source for fuel economy information, allows users to share gas mileage information on their vehicles. The histogram below shows the distribution of gas mileage in miles per gallon (MPG) from 14 users who drive a 2012 Toyota Prius. The sample mean is 53.3 MPG and the standard deviation is 5.2 MPG. Note that these data are user estimates and since the source data cannot be verified, the accuracy of these estimates are not guaranteed. (a) The EPA claims that a 2012 Prius gets 50 MPG (city and highway mileage combined). Do these data provide strong evidence against this estimate for drivers who participate on fueleconomy.gov? The test statistic is: __________________(please round to two decimal places)The p-value:___________________________ for this hypothesis test is: (please round to four decimal places)(c) Please comment on the primary thing that is wrong about the following statement: There is sufficient evidence…
A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 44 participants in the treatment group lowered their cholesterol levels by a mean of 18.7 points with a standard deviation of 3.3 points. The 39 participants in the control group lowered their cholesterol levels by a mean of 18.1 points with a standard deviation of 2.1 points. Assume that the population variances are not equal and test the company’s claim at the 0.02 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha : μ1⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯μ2 Step 2 of 3: what is the test statistic Step 3 of 3: draw a conclusion, fail or reject. Is…
A local church parish wants to raise money to add to their campus. In a sample from a previous fund raising campaign, the parish found that of the 131 people in the sample they contacted, that 69 actually contributed money. Of those that contributed money, the average contribution was $857 with a standard deviation of $265. In the recent fundraising campaign, a sample of 95 people revealed that 48 have contributed money with an average contribution of $1109 and a standard deviation of $339. When testing (at the 5% level of significance) whether the average amount contributed has increased in the current campaign compared to the previous campaign, what is the test statistic? (please round your answer to 2 decimal places)

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