Nationally, patients who go to the emergency room wait an average of 6 hours to be admitted into thehospital. Do patients at rural hospitals have a different waiting time? The 12 randomly selected patientswho went to the emergency room at rural hospitals waited an average of 5.9 hours to be admitted into thehospital. The standard deviation for these 12 patients was 1.6 hours. What can be concluded at the a =0.05 level of significance level of significance?a. For this study, we should use t-test for a population meanb. The null and alternative hypotheses would be:OºOºHo:H₁: U#c. The test statisticOFd. The p-value =e. The p-value isMa6f. Based on this, we should fail to reject6(please show your answer to 3 decimal places.)(Please show your answer to 4 decimal places.)the null hypothesis.g. Thus, the final conclusion is that ....The data suggest that the population mean awaiting time to be admitted into the hospitalfrom the emergency room for patients at rural hospitals is not significantly different from 6hours at a = 0.05, so there is statistically insignificant evidence to conclude that theom for

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average retirement age in America is 63 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 66, 60, 62, 71, 58, 73, 60, 72, 70, 61, 57 What can be concluded at the the a 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: uv = 63 H: uv> c. The test statistic ? = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that O The data suggest the population mean retirement age for small business owners is not significantly different from 63 at a = 0.05, so there is insufficient evidence to conclude that the population mean…
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 23.5 with a standard deviation of 4.3, while the 200 students in group 2 had a mean score of 17.7 with a standard deviation of 4.1. Complete parts (a) and (b) below. (a) Determine the 95% confidence interval for the difference in scores, μ1−μ2. Interpret the interval. The lower bound is __. The upper bound is ___ (Round to three decimal places as needed.) B Interpret the interval. Choose the correct answer below. A. The researchers are 95% confident that the difference of the means is in the interval. B. There is a 95% probability that the difference of the means is…
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 5% level of significance. Give answer to at least 4 decimal places. Hours 46 49 58 55 49 68 45 48 46 45 51 50 What are the correct hypotheses? H0: hoursH1: hours Based on the hypotheses, find the following:Test Statistic=p-value= The correct decision is to . The correct summary would be: that the mean number of hours of all employees at start-up companies work more than the US mean of 47 hours.
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 10% level of significance. Give answer to at least 4 decimal places. Hours 49 40 58 52 49 70 49 59 47 49 53 55 What are the correct hypotheses? H0: hoursH1: hours Based on the hypotheses, find the following:Test Statistic=p-value= The correct decision is to . The correct summary would be: that the mean number of hours of all employees at start-up companies work more than the US mean of 47 hours.
50 smokers were questioned about the number of hours they sleep each day. We want to test the hypothesis that the smokers need less sleep than the general public which needs an average of 7.7 hours of sleep. We follow the steps below. Compute a rejection region for a significance level of .05. A. If the sample mean is 7.5 and the standard deviation is .5, what can you conclude?
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 24.9 with a standard deviation of 4.3, while the 200 students in group 2 had a mean score of 17.2 with a standard deviation of 3.4. Complete parts (a) and (b) below. (a) Determine the 95% confidence interval for the difference in scores, µ, - H2. Interpret the interval. The lower bound is The upper bound is. (Round to three decimal places as needed.)
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 26.3 with a standard deviation of 5.2, while the 200 students in group 2 had a mean score of 17.6 with a standard deviation of 2.8. Complete parts (a) and (b) below. (a) Determine the 90% confidence interval for the difference in scores, μ1−μ2. Interpret the interval. The lower bound is nothing. The upper bound is nothing. (Round to three decimal places as needed.)
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 10% level of significance. Give answer to at least 4 decimal places. Hours 48 43 58 51 45 62 47 55 49 49 52 53 a. What are the correct hypotheses? Ho: Select an answer H₁: Select an answer b. Test Statistic = Based on the hypotheses, find the following: c. p-value = ? 0 ? 0 d. The correct decision is to Select an answer Add Work hours hours e. The correct summary would be: Select an answer hours of all employees at start-up companies work more than the US mean of 47 hours. that the mean number of
Jess2.4 employees leaving per month, with a standard deviation of 0.5. She decided to see if using a new benefits package would affect her average. She used the new benefits package for 13 months. For those 13 months, Jessica got an average of 2.6 employees leaving. She wants to know if the new benefits package caused her to get a different number of employees leaving per month. She conducts a one-mean hypothesis at the 5% significance level, to see if the new benefits package caused her to get a different number of employees leaving per month. Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ=2.4; Ha:μ≠2.4, which is a two-tailed test. H0:μ=2.4; Ha:μ<2.4, which is a left-tailed test. H0:μ=2.4; Ha:μ>2.4, which is a right-tailed test. H0:μ=2.6; Ha:μ≠2.6, which is a left-tailed test.
(a) Using the information above, part of the ANOVA table is: Source of variation Sum of squares Region I error II Find the values of (round off to two decimal points) (1) I (11) II
Nationally, patients who go to the emergency room wait an average of 4 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 13 randomly selected patients who went to the emergency room at rural hospitals waited an average of 3.2 hours to be admitted into the hospital. The standard deviation for these 13 patients was 2.9 hours. What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Select an answer V Select an answer c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please showyour answer to 4 decimal places.) e. The p-value is 7 v f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest that the population mean awaiting time to be admitted into the hospital from the emergency room for patients at…

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