How many degrees of freedom should they use in their calculations? df=
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A: n1=15, x¯1=50, SS1=210n2=9, x¯2=56, SS2=190
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A: From the provided information, n1=50x1=85s1=4n2=50x2=80s2=3 Level of significance (α) = 0.01
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A: Givensample size(n)=10Mean(x)=125standard deviation(s)=24significance level=0.05
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A: The hypotheses can be constructed as: H0: µ = 6.1 H1: µ ≠ 6.1 Sample size (n) = 40 Assume level of…
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A: SolutionLet µ1 be the population mean score of group 1 students who had taken a statistical method…
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A: given that, To calculate the t-statistic, we need to use the formula: t =(x̄ - μ) s/n where: x̄…
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A: Given n1=n2=31 S1=1242 S2=2258 X1-bar=105965 X1-bar=104291
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A: Givensample size(n)=38Mean(x)=3.6standard deviation(s)=2significance level(α)=0.05
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A: Please see Below
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A: xbar = 48 mu = 32 s = 6 n =20
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A: Introduction: Denote μ0 as the pretest or hypothesized mean creativity score, σ as the population…
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A: The mean is 10462 and the standard deviation is 2512.
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A: Given information, x¯=48s=6n=20μ=32 A) Test statistic: t=x¯-μsn =48-32620 =11.9257 Critical values:…
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A: Given info: The test scores is normally distributed with mean of 175 and standard deviation of 20.
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A: Given: n1 = 100 X1 = 1175 Hours S1 = 105 Hours n2 = 100 X2 = 1220 Hours S2 = 80 Hours Significance…
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A: Introduction: Denote μ1, μ2 as the true population mean scores for test versions B and C…
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A: Given The data is as follows: Sample size, n=100 Sample mean, x¯=29 Sample standard deviation, s=5…
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A: The objective of this question is to determine the decision rule for rejecting the null hypothesis…
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A: sample size(n)=11Mean()=124standard deviation(s)=24significance level()=0.10claim is that μ, the…
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A: Given, n1=10, n2=10, σ1=6400 and σ2=6600 Level of significance=0.10
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Q: He can we answer?
A: State the Hypotheses• Null Hypothesis (H0) : The mean score after the program is (μ0=45) (no…
Suppose that Rachel studied for the Graduate Management Admission Test (GMAT) using a well-known preparation class and was thrilled to receive a total score of 760. Her friend Eric, however, thinks she would have scored just as well without the class.
To test the efficacy of the class, they obtain a small but random sample of 15 test results from other students using the same class. This sample's average is 567.23 with a standard deviation of 182.05. In comparison, the national average was 550.12. Assume the population's results are
Rachel and Eric decide to perform a two-tailed ?‑test at a significance level of ?=0.05. How many degrees of freedom should they use in their calculations?
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- We are trying whether, a new low fat diet actually helps obese people lose weight. 100 randomly obese people are assigned to group 1 and put on a low fat-diet. another 100 people are assigned to group 2 and put on a diet of approximately the same amount of food, but not as low in fat. After 4 months, the mean net weight loss was 9.31 pounds for group 1 with a standard deviation of 4.67 pounds, and for group 2 the mean net weight loss was 7.40 pounds with a standard deviation of 4.04 pounds. Is the low-fat diet more effective? Perform a hypothesis test at the 5% significance level a) Define Parameters and state null and alternative hypothesis b) Find test statistics c) Find p-value d) ConclusionA study was conducted to investigate the effect of a new drug on blood pressure. A sample of 25 patients was randomly selected and their blood pressure was measured both before and after taking the drug. The sample mean blood pressure before taking the drug was 120 mmHg and the sample mean blood pressure after taking the drug was 118 mmHg. The sample standard deviation for the blood pressure before taking the drug was 4 mmHg and the sample standard deviation for the blood pressure after taking the drug was 5 mmHg. Test the hypothesis that the average blood pressure after taking the drug is lower than the average blood pressure before taking the drug using a 0.01 level of significance.A forestry researcher is conducting a study of trees in the upper midwest. He selects a random sample of 125 red maple trees and measures the trunk diameter of each. The mean of the sample is 25 inches with a standard deviation of 5.2 inches, use this to find a 95% confidence interval for the mean trunk diameter of all red maple trees.
- A researcher wants to compare the effectiveness of two different study techniques for a test. The mean test score for the first technique is 75 with a standard deviation of 5, and the mean test score for the second technique is 80 with a standard deviation of 4. The sample size for each group is 20. What is the 95% Confidence Interval for the difference in the mean test scores for the two techniques?A researcher gathered a sample of participants who volunteered for a studying of phobias. She measured anxiety level of participants as they viewed photos of spiders and again when they viewed puppies. Which statistical test is appropriate for this study and why?At BYU-Idaho there has been a lot of interest in the performance of students in online classes. Generally, administrators are interested to know if there is a difference in the learning of students who take an online course compared to those who take a traditional course. A study was done to see if the grade received in the course is related to the type of course. Researchers collected the grades of randomly selected students who were taking a traditional Business Statistics class and compared those with the grades earned by randomly selected students who were taking an online Business Statistics class. The data are shown in the table below. Grade A B с D F You want to determine if a student's grade and the type of course he or she is enrolled in are independent. Use a level of significance of a = 0.01. State the null and alternative hypothesis for this test. O Ho: Traditional and online courses are not independent. H₂: Traditional and online courses are independent. O Ho: Traditional…
- Two teaching methods and their effects on science test scores are being reviewed. A random sample of 1313 students, taught in traditional lab sessions, had a mean test score of 78.478.4 with a standard deviation of 5.85.8. A random sample of 1717 students, taught using interactive simulation software, had a mean test score of 85.385.3 with a standard deviation of 4.14.1. Do these results support the claim that the mean science test score is lower for students taught in traditional lab sessions than it is for students taught using interactive simulation software? Let μ1�1 be the mean test score for the students taught in traditional lab sessions and μ2�2 be the mean test score for students taught using interactive simulation software. Use a significance level of α=0.01�=0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 3 of 4 : Determine the decision rule for rejecting the null hypothesis H0�0. Round your…A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.Logan and Brian began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Logan took a test in Art History and earned a 76.8, and Brian took a test in English and earned a 68.9. Use the fact that all the students' test grades in the Art History class had a mean of 71.9 and a standard deviation of 11.6, and all the students' test grades in English had a mean of 61 and a standard deviation of 9.4 to answer the following questions.a) Calculate the z-score for Logan's test grade.z=z= [Round your answer to two decimal places.] b) Calculate the z-score for Brian's test grade.z=z= [Round your answer to two decimal places.]c) Which person did relatively better? Logan Brian They did equally well.
- The administrator at your local hospital states that on weekends the average wait time for emergency room visits is 10 minutes. Based on discussions you have had with friends who have complained on how long they waited to be seen in the ER over a weekend, you dispute the administrator’s claim. You decide to test your hypothesis. Over the course of a few weekends, you record the wait time for 40 randomly selected patients. The average wait time for these 40 patients is 11 minutes with a standard deviation of 3 minutes. Do you have enough evidence to support your hypothesis that the average ER wait time is different than 10 minutes? You opt to conduct the test at an α = 0.025 level of significance.In an article on Flurry Blog, a gaming marketing gap for men between the ages of 30 and 40 is identified. You are researching a startup game targeted at the 35-year-old demographic. Your idea is to develop a strategy game that can be played by men from their late 20s through their late 30s. Based on the article's data, industry research shows that the average strategy player is 28 years old with a standard deviation of 4.8 years. You take a sample of 120 randomly selected gamers. If your target market is 29- to 35-year-olds. What is the probability of men wanting to play? Should you continue with your development strategy? I don't know 2 attempts Exit Submit answer 184 -31.133 MAR 28 MacBook Ai F9 F7 F8 F6 F5 20 F3 F4 & 23 2$ 8 9- 3 4 R. Y. J ाई F.Historically, the mean age of all Memphis residents has been 40 years. You believe this has changed. You take a random sample of 130 Memphis residents and find that their mean age is 36 years with a standard deviation of 17 years. Can you conclude that the mean age of all Memphis residents has changed from 40 years. For the hypothesis testing scenario above, compute the test statistic. For the hypothesis testing scenario above, you conclude that the mean age of all Memphis residents has changed from 40 years at the 0.05 significance level. Compute the 95% confidence interval to estimate the mean age of all Memphis residents.