A compound has a pKa of 7.4. You have made up 100 mL of a 1.0 M solution ofthis compound at pH 8.0. What is the ratio of unprotonated to protonatedforms of the molecule?80%○ 66.7%100%○ 50%○ 20%

To find the ratio of the unprotonated to protonated form of the molecules, we'll use the…

Answered: A compound has a pKa of 7.4. You have…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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calculate the pH of a 0.10M solution of formic acid. the Ka of formic acid is 1.8x10^-4
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pH of solution 14.00 12.00 10.00 8.00 6.00 First 4.00 equivalence point 2.00 0 First midpoint Second equivalence point Third midpoint pH = pKa=12.32 Third equivalence point HPO4(aq) + OH(aq) PO4(aq) + H2O(1) Second midpoint pH = pKa = 7.21 H2PO4 (aq) + OH(aq) HPO42 (aq) + H2O(1) Using the Henderson- Hasselback equation, show how to create 2L of a 0.1 M KPhos pH 7.5 buffer using K2HPO4 and KH2PO4. The chart to the left should help you understand what pKa to start with. Show your work. pH = pKa = 2.16 H3PO4(aq) + OH(aq) H2PO4(aq) + H2O(l) 25.0 50.0 75.0 100.0 Volume of NaOH added (mL)
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What are the components of a lysine buffer at pH 9.2? Refer to the following forms of lysine: A H B H H H H;N-C-COOH H;N-C-coo- H,N-C-c0- H,N-C-coo- CH2 CH2 CH2 CH. CH2 CH, pk-2.17 pk=4.04 pk=12.48 CH, CH, ÇH2 CH, CH. CH, CH, CH. CH, CH, NH, NH, NH, NH, . A and B .C and D .B and C . A and D B and D

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A compound has a pKa of 7.4. You have made up 100 mL of a 1.0 M solution of this compound at pH 8.0. What is the ratio of unprotonated to protonated forms of the molecule? 80% ○ 66.7% 100% ○ 50% ○ 20%