Question 6 of 36RetryA buffer solution contains dissolved C6H5NH2 andC6H5NH3CI. The initial concentration of C6H5NH2 is 0.50M and the pH of the buffer is 4.20. Determine theconcentration of C6H;NH3* in the solution. The value ofKb for C6H5NH2 is 3.8 x 10-10.12NEXT >Let x represent the original concentration of C6H5NH3* in the water. Based on the givenvalues, set up the ICE table in order to determine the unknown.C6H;NH2(aq) +H20(1)ОН (ад)+ CgH;NH;*(aq)Initial (M)0.50Change (M)Equilibrium(M)-1.6 x 10 10Incorrect, 2 attempts remainingYour Initial concentration for C,H5NH3* is incorrect. Revisit the problem statement to determine the initial concentration of acidor base. Also, make sure that your values are in the correct concentration units, not mass or moles!Your Change in concentration for C6H5NH2 is incorrect. In this problem, you should use the given pH to determine theconcentration of H3O* or OH at Equilibrium as appropriate. From there, you should be able to determine the Change of eachspecies, which is the difference between the Equilibrium and Initial concentration. Recall that pH = -log([H3O*]) and that[H;O*][OH¯] = 1 × 10-14%3DYour Change in concentration for OH" is incorrect. In this problem, you should use the given pH to determine theconcentration of H30* or OH at Equilibrium as appropriate. From there, you should be able to determine the Change of eachspecies, which is the difference between the Equilibrium and Initial concentration. Recall that pH = -log([H3oʻ) and that[H;O*][OH] = 1 × 10-14

A buffer solution is formed by the dissolution of weak acid and its pH and pKa values should be…

A buffer solution contains dissolved C6H5NH2 and C6H5NH3CI. The initial concentration of C6H5NH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6H5NH3* in the solution. The value of Kb for C6H5NH2 is 3.8 × 10¯10. 2 3 NEXT > Let x represent the original concentration of C6H;NH3* in the water. Based on the given values, set up the ICE table in order to determine the unknown. C6H5NH2(aq) + H2O(1) OH (aq) + C6H5NH3*(aq) Initial (M) 0.50 Change (M) Equilibrium |(M) -1.6 x 10-10 II

A buffer solution contains dissolved C6H5NH2 and C6H5NH3CI. The initial concentration of C6H5NH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6H5NH3* in the solution. The value of Kb for C6H5NH2 is 3.8 × 10¯10. 2 3 NEXT > Let x represent the original concentration of C6H;NH3* in the water. Based on the given values, set up the ICE table in order to determine the unknown. C6H5NH2(aq) + H2O(1) OH (aq) + C6H5NH3*(aq) Initial (M) 0.50 Change (M) Equilibrium |(M) -1.6 x 10-10 II

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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please help on my buffers worksheet for chem
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A buffer solution contains dissolved C6H5NH2 and C6H;NH3CI. The initial concentration of C6H5NH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6H5NH3* in the solution. The value of Kb for C6H5NH2 is 3.8 x 10 10. ( PREV 1 3 NEXT > Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not combine or simplify terms. Kp 3.8 x 10-10 %3D %3D 5 RESET [0] [0.50] [x] [2x] [4.20] [6.3 x 10-5) [1.6 x 10-10] [3.8 х 1011 [x + 4.20] [x - 4.20] [x + 6.3 x 10-51 [x - 6.3 х 10-5] [x + 1.6 x 101°] [x - 1.6 x 10-10] [x + 3.8 x 10-101 [x - 3.8 x 101°]
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12:04 Question 4 of 9 Submit A buffer solution contains dissolved C6H5NH2 and C6H;NH;CI. The initial concentration of C6HŞNH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6HŞNH3* in the solution. The value of Kb for C6H;NH2 is 3.8 × 10-1º. 1 2 3 Let x represent the original concentration of C6H,NH,* in the water. Based on the given values, set up the ICE table in order to determine the unknown. C6H5NH2(at H20(1) = OH-(aq) +C6H5NH3*(a Initial (M) Change (M) Equilibrium (M) 5 RESET 0.50 - 4.20 -4.20 6.3 x 10-5 -6.3 x 10-5 1.6 x 10-10 -1.6 x 10-10 3.8 x 10-10 -3.8 x 10-10 x + 4.20 x - 4.20 x + 6.3 x 10-5 х - 6.3 х 10-6 x + 1.6 x 10-10 x - 1.6 x 10-10 x + 3.8 x 10-10 x - 3.8 x 10-10 Tap here or pull up for additional resources