A buffer solution contains dissolved C6H5NH2 and C6H;NH3CI. The initial concentration of C6H5NH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6H5NH3* in the solution. The value of Kb for C6H5NH2 is 3.8 × 10¬1º. 1 2 3 NEXT > Let x represent the original concentration of C6H;NH3* in the water. Based on the given values, set up the ICE table in order to determine the unknown. C6H;NH2(aq) + H20(1) = OH (aq) +C6H5NH;*(aq) Initial (M) |Change (M) Equilibriu m (M). RESET 0.50 4.20 -4.20 6.3 x 10-5 -6.3 x 10-5 - 1.6 x 10-10 -1.6 x 10-10 3.8 x 1010 -3.8 x 10-10 x + 4.20 x - 4.20 x+ 6.3 x 10-5 x - 6.3 x 10-5 x + 1.6 x 10-10 x - 1.6 x 1010 x + 3.8 x 10"10 x - 3.8 x 1010

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A buffer solution contains dissolved C6H5NH2 and C6H;NH3CI.
The initial concentration of C6H5NH2 is 0.50 M and the pH of the
buffer is 4.20. Determine the concentration of C6H5NH3* in the
solution. The value of Kb for C6H;NH2 is 3.8 x 10 10.
1
2
3
NEXT >
Let x represent the original concentration of C6H;NH3* in the water. Based on
the given values, set up the ICE table in order to determine the unknown.
C6H;NH2(aq) +
H20(1)
OH (aq) +C6H5NH3*(aq)
Initial (M)
|Change
(M)
Equilibriu
m (M).
5 RESET
0.50
4.20
-4.20
6.3 x 10-5
-6.3 x 10-5
1.6 x 1010
-1.6 x 10-10
3.8 x 10-10
-3.8 x 10-10
x + 4.20
x - 4.20
x + 6.3 x 10-5
x - 6.3 x 10-5
x + 1.6 x 1010
x - 1.6 x 10-10
|x+3.8 х 10-10
x - 3.8 x 1010
Transcribed Image Text:A buffer solution contains dissolved C6H5NH2 and C6H;NH3CI. The initial concentration of C6H5NH2 is 0.50 M and the pH of the buffer is 4.20. Determine the concentration of C6H5NH3* in the solution. The value of Kb for C6H;NH2 is 3.8 x 10 10. 1 2 3 NEXT > Let x represent the original concentration of C6H;NH3* in the water. Based on the given values, set up the ICE table in order to determine the unknown. C6H;NH2(aq) + H20(1) OH (aq) +C6H5NH3*(aq) Initial (M) |Change (M) Equilibriu m (M). 5 RESET 0.50 4.20 -4.20 6.3 x 10-5 -6.3 x 10-5 1.6 x 1010 -1.6 x 10-10 3.8 x 10-10 -3.8 x 10-10 x + 4.20 x - 4.20 x + 6.3 x 10-5 x - 6.3 x 10-5 x + 1.6 x 1010 x - 1.6 x 10-10 |x+3.8 х 10-10 x - 3.8 x 1010
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