NaOH: 0.100 M Molarities of Solutions HCI: 0.1007 C2H3O2: 0.1005 M M-HC2H3O2: Part 1 - Titration of Hydrochloric Acid becubong ovisnotsuite griau bloe piles to solar mob of Using your titration curve, what is the mL base needed to reach the equivalence point? CORDAS Jag tog nolluloa bien ne bs agnied bio 25 nulov aumey He To Joig leciiaste axem uov umLoitsu (A clients es wolle ndog conalovispa en bron Han qe For each point shown below in the titration, record your measured pH from your data, then calculate the pH of the solution. Show your work for all calculations in the space provided. fomento orfT [HC1] = [H+] anos evig illw blos Acow a bris (10moq nobsilit 1. What was the pH of the hydrochloric acid before any base was added? -log[H+] = -log[0.1007] Measured pH = 4.1 pH = -log [H+] where [HCI] = [H+] Calculated pH: = 1.0 06 Hq =0.99697 ~1.0 2. What was the pH after 10.0 mL of sodium hydroxide solution was added? Measured pH = 1.3 Volume of HCI solution in liters: 002 0.01 net Um L Moles of HCI = Volume of HCI solution x Molarity of HCI: ___ moles protas p Volume of NaOH solution in liters: 1) goes riw (bios oitoon) bios sew a pr Moles of NaOH = Volume of NaOH solution x Molarity of NaOH: Amount of HCI remaining = Total moles of HCI - moles of HCI used: Total volume of solution (volume of HCI + NaOH in liters): Molarity of remaining HCI (moles / volume of solution): pH = -log [H+] where [HCI] = [H+] le al 3 LEA to M moles moles Calculated pH = Conmetel natto Jaom el blos y nos od krivds thing of „Ha = Ra etertwining preleviupe ani Meryllexe

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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NaOH:
0.100
M
Molarities of Solutions
HCI: 0.1007 C2H3O2: 0.1005 M
M-HC2H3O2:
Part 1 - Titration of Hydrochloric Acid becubong ovisnotsuite griau bloe piles to solar mob of
Using your titration curve, what is the mL base needed to reach the equivalence point? CORDAS
Jag tog nolluloa bien ne bs
agnied bio
25 nulov aumey He To Joig leciiaste axem uov
umLoitsu (A
clients es wolle
ndog conalovispa en bron Han qe
For each point shown below in the titration, record your measured pH from your data, then calculate the pH of
the solution. Show your work for all calculations in the space provided. fomento
orfT
[HC1] = [H+]
anos evig illw blos Acow a bris (10moq
nobsilit
1. What was the pH of the hydrochloric acid before any base was added? -log[H+] = -log[0.1007]
Measured pH
=
4.1
pH = -log [H+] where [HCI] = [H+]
Calculated pH:
=
1.0
06
Hq
=0.99697
~1.0
2. What was the pH after 10.0 mL of sodium hydroxide solution was added?
Measured pH =
1.3
Volume of HCI solution in liters:
002
0.01
net Um
L
Moles of HCI = Volume of HCI solution x Molarity of HCI: ___ moles protas p
Volume of NaOH solution in liters: 1) goes riw (bios oitoon) bios sew a pr
Moles of NaOH = Volume of NaOH solution x Molarity of NaOH:
Amount of HCI remaining = Total moles of HCI - moles of HCI used:
Total volume of solution (volume of HCI + NaOH in liters):
Molarity of remaining HCI (moles / volume of solution):
pH = -log [H+] where [HCI] = [H+]
le al
3
LEA to
M
moles
moles
Calculated pH = Conmetel natto Jaom el blos y nos od krivds thing of
„Ha = Ra etertwining preleviupe ani Meryllexe
Transcribed Image Text:NaOH: 0.100 M Molarities of Solutions HCI: 0.1007 C2H3O2: 0.1005 M M-HC2H3O2: Part 1 - Titration of Hydrochloric Acid becubong ovisnotsuite griau bloe piles to solar mob of Using your titration curve, what is the mL base needed to reach the equivalence point? CORDAS Jag tog nolluloa bien ne bs agnied bio 25 nulov aumey He To Joig leciiaste axem uov umLoitsu (A clients es wolle ndog conalovispa en bron Han qe For each point shown below in the titration, record your measured pH from your data, then calculate the pH of the solution. Show your work for all calculations in the space provided. fomento orfT [HC1] = [H+] anos evig illw blos Acow a bris (10moq nobsilit 1. What was the pH of the hydrochloric acid before any base was added? -log[H+] = -log[0.1007] Measured pH = 4.1 pH = -log [H+] where [HCI] = [H+] Calculated pH: = 1.0 06 Hq =0.99697 ~1.0 2. What was the pH after 10.0 mL of sodium hydroxide solution was added? Measured pH = 1.3 Volume of HCI solution in liters: 002 0.01 net Um L Moles of HCI = Volume of HCI solution x Molarity of HCI: ___ moles protas p Volume of NaOH solution in liters: 1) goes riw (bios oitoon) bios sew a pr Moles of NaOH = Volume of NaOH solution x Molarity of NaOH: Amount of HCI remaining = Total moles of HCI - moles of HCI used: Total volume of solution (volume of HCI + NaOH in liters): Molarity of remaining HCI (moles / volume of solution): pH = -log [H+] where [HCI] = [H+] le al 3 LEA to M moles moles Calculated pH = Conmetel natto Jaom el blos y nos od krivds thing of „Ha = Ra etertwining preleviupe ani Meryllexe
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