Four solutions of unknown HClHCl concentration are titrated with solutions of NaOHNaOH. The following table lists the volume of each unknown HClHCl solution, the volume of NaOHNaOH solution required to reach the equivalence point, and the concentration of each NaOHNaOH solution. HClHCl Volume (mL)(mL) NaOHNaOH Volume (mL)(mL) [NaOH][NaOH] (M)(M) 24.00 mLmL 23.44 mLmL 0.1201 MM 11.00 mLmL 20.22 mLmL 0.0952 MM 23.00 mLmL 11.88 mLmL 0.1128 MM 3.00 mLmL 5.88 mLmL 0.1325 MM 1. Calculate the concentration (in MM) of the unknown HClHCl solution in the first case. HClVolume (mL) NaOH Volume (mL) [NaOH](M) 24.00 mL 23.44 mL 0.1201 M 2. Calculate the concentration (in MM) of the unknown HClHCl solution in the second case. HCl Volume (mL) NaOH Volume (mL) [NaOH] (M) 11.00 mL 20.22 mL 0.0952 M 3. Calculate the concentration (in MM) of the unknown HClHCl solution in the third case. HCl Volume (mL) NaOH Volume (mL) [NaOH][NaOH] (M) 23.00 mL 11.88 mL 0.1128 M 4. Calculate the concentration (in MM) of the unknown HClHCl solution in the fourth case. HCl Volume (mL) NaOH Volume (mL) [NaOH] (M) 3.00 mL 5.88 mL 0.1325 M
Four solutions of unknown HClHCl concentration are titrated with solutions of NaOHNaOH. The following table lists the volume of each unknown HClHCl solution, the volume of NaOHNaOH solution required to reach the equivalence point, and the concentration of each NaOHNaOH solution. HClHCl Volume (mL)(mL) NaOHNaOH Volume (mL)(mL) [NaOH][NaOH] (M)(M) 24.00 mLmL 23.44 mLmL 0.1201 MM 11.00 mLmL 20.22 mLmL 0.0952 MM 23.00 mLmL 11.88 mLmL 0.1128 MM 3.00 mLmL 5.88 mLmL 0.1325 MM 1. Calculate the concentration (in MM) of the unknown HClHCl solution in the first case. HClVolume (mL) NaOH Volume (mL) [NaOH](M) 24.00 mL 23.44 mL 0.1201 M 2. Calculate the concentration (in MM) of the unknown HClHCl solution in the second case. HCl Volume (mL) NaOH Volume (mL) [NaOH] (M) 11.00 mL 20.22 mL 0.0952 M 3. Calculate the concentration (in MM) of the unknown HClHCl solution in the third case. HCl Volume (mL) NaOH Volume (mL) [NaOH][NaOH] (M) 23.00 mL 11.88 mL 0.1128 M 4. Calculate the concentration (in MM) of the unknown HClHCl solution in the fourth case. HCl Volume (mL) NaOH Volume (mL) [NaOH] (M) 3.00 mL 5.88 mL 0.1325 M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Four solutions of unknown HClHCl concentration are titrated with solutions of NaOHNaOH. The following table lists the volume of each unknown HClHCl solution, the volume of NaOHNaOH solution required to reach the equivalence point, and the concentration of each NaOHNaOH solution.
| HClHCl Volume (mL)(mL) | NaOHNaOH Volume (mL)(mL) | [NaOH][NaOH] (M)(M) |
| 24.00 mLmL | 23.44 mLmL | 0.1201 MM |
| 11.00 mLmL | 20.22 mLmL | 0.0952 MM |
| 23.00 mLmL | 11.88 mLmL | 0.1128 MM |
| 3.00 mLmL | 5.88 mLmL | 0.1325 MM |
1. Calculate the concentration (in MM) of the unknown HClHCl solution in the first case.
| HClVolume (mL) | NaOH Volume (mL) | [NaOH](M) |
| 24.00 mL | 23.44 mL | 0.1201 M |
2. Calculate the concentration (in MM) of the unknown HClHCl solution in the second case.
| HCl Volume (mL) | NaOH Volume (mL) | [NaOH] (M) |
| 11.00 mL | 20.22 mL | 0.0952 M |
3. Calculate the concentration (in MM) of the unknown HClHCl solution in the third case.
| HCl Volume (mL) | NaOH Volume (mL) | [NaOH][NaOH] (M) |
| 23.00 mL | 11.88 mL | 0.1128 M |
4. Calculate the concentration (in MM) of the unknown HClHCl solution in the fourth case.
| HCl Volume (mL) | NaOH Volume (mL) | [NaOH] (M) |
| 3.00 mL | 5.88 mL | 0.1325 M |
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