A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. Mouse #3 is mated to a brown female (#5) with normal cholesterol. If 4 mice are produced from this cross, what is the probability that all 4 will have brown fur?
In mice, the trait for high cholesterol is specified by a dominant allele designated
HC, whereas the wild-type allele for normal cholesterol levels is designated hc.
Black fur is specified by a recessive allele designated bl, whereas the wild-type
allele which gives brown fur is designated BL. The genes for both of these traits
are 30cM apart on the same autosome. A brown female (#1) with high cholesterol
is mated to a black male (#2) with normal cholesterol. The progeny from this cross
include a brown male (#3) with high cholesterol and a black female (#4) with
normal cholesterol. Mouse #3 is mated to a brown female (#5) with normal
cholesterol. If 4 mice are produced from this cross, what is the probability that all 4
will have brown fur?
Step by step
Solved in 3 steps with 1 images