In Drosophila, a cross was made between females and wild-type males. The female parents expressed the three X-linked recessive traits miniature wing (m), ebony body (e) and cinnabar eye (c). In the F1, all females were wild type, while all males expressed all three mutant traits. The cross was carried to the F2 generation, and 1500 offspring were produced. 412 Miniature wing, ebony body, cinnabar eye Wild type Ebony body, cinnabar eye Miniature wing Miniature wing, cinnabar eye Ebony body Miniature wing, ebony body Cinnabar eye 403 211 224 103 96 23 28 Using proper nomenclature, determine the genotypes of the females and males in generation P and F1. (i) (ii) What is the correct order of the genes? (iii) Construct a genetic map showing the correct order and distances between these genes.

In Drosophila, a cross was made between females and wild-type males. The female parents expressed the three X-linked recessive traits miniature wing (m), ebony body (e) and cinnabar eye (c). In the F1, all females were wild type, while all males expressed all three mutant traits. The cross was carried to the F2 generation, and 1500 offspring were produced. 412 Miniature wing, ebony body, cinnabar eye Wild type Ebony body, cinnabar eye Miniature wing Miniature wing, cinnabar eye Ebony body Miniature wing, ebony body Cinnabar eye 403 211 224 103 96 23 28 Using proper nomenclature, determine the genotypes of the females and males in generation P and F1. (i) (ii) What is the correct order of the genes? (iii) Construct a genetic map showing the correct order and distances between these genes.

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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In Drosophila, females heterozygous for the recessive alleles c, d, and e were crossed to males homozygous recessive for these three mutant genes. The phenotypes of the resulting progeny were: cd+ 350 ++e 350 c + e 51 + d + 49 c + + 100 + d e 100 _________ _____ Total progeny 1000 How were the three pairs of alleles arranged in the heterozygous females? a. +d+/c+e B. cde/+++ C. +de/c++ D. cd+/++e
In Drosophila, males from a true-breeding stock with raspberry-colored eyes were mated to females from a true-breeding stock with sable-colored bodies. In the F1 generation, all the females had wild-type eye and body color, while all the males had wild-type eye color but sable-colored bodies. When F1 males and females were mated to each other, the F2 was composed of: 216 females with wild-type eyes and wild-type bodies 223 females with wild-type eyes and sable bodies 191 males with wild-type eyes and sable bodies 188 males with raspberry eyes and wild-type bodies 23 males with wild-type eyes and bodies 27 males with raspberry eyes and sable bodies Which statements are consistent with the above data? (Select all correct answers.) The alleles causing the raspberry-colored eye and sable-colored body phenotypes are dominant to the corresponding wild-type alleles The genes controlling raspberry-colored eyes and sable-colored bodies map…
In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cM
Consider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?
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Two fruit flies (Drosophila melanogaster) were crossed. The cross was between a homozygous red-eyed, wingless female and a white-eyed male heterozygous for wings. Recall that red eyes (R) is dominant over white eyes (r) and is inherited on the X chromosome (sex-linked) and as such, eye colour alleles should be written as superscript. In addition, the autosomal trait wings (W) is dominant over wingless (w). 1. List the female genotype 2. List the male genotype 3. Construct a Punnett Square for this dihybrid cross on a piece of paper, to determine what the offspring of such a cross would be with respect to sex, eye colour & wings. 4. Using the information from your Punnett Square answer the following: a. What genotypes did you get (list all genotype combinations; if you have more than one of the same kind, you do NOT have to re-list it.) b. What are the phenotypic ratios of the offspring with respect to sex, eye colour and wings?