A A A B В В Concentration of sugar Concentration of sugar А 36% В 15% Concentration of sugar A 21% В 60% Solution is A 44% В 21% Solution is Solution is A A A B B Concentration of sugar Concentration of sugar Concentration of sugar A 58% В 25% Solution is А 30% в 30% Solution is A 0% В 35 Solution is A A A B В B Concentration of sugar Concentration of sugar Α 10% В 40% A 8% В 50% Concentration of sugar A 15% В 45% Solution is Solution is Solution is

A A A B В В Concentration of sugar Concentration of sugar А 36% В 15% Concentration of sugar A 21% В 60% Solution is A 44% В 21% Solution is Solution is A A A B B Concentration of sugar Concentration of sugar Concentration of sugar A 58% В 25% Solution is А 30% в 30% Solution is A 0% В 35 Solution is A A A B В B Concentration of sugar Concentration of sugar Α 10% В 40% A 8% В 50% Concentration of sugar A 15% В 45% Solution is Solution is Solution is

Name: In each problem below draw an arrow showing which way water will move/
Uploaded: 2022-12-02T03:55:46.000Z
Channel: Bartleby
Description: In each problem below draw an arrow showing which way water will move/flow. Is the solution hypertonic, hypotonic or isotonic? AAABВВConcentration of sugarConcentration of sugarА 36%В 15%Concentration of sugarA 21%В 60%Solution isA 44%В 21%Solution i

Curren'S Math For Meds: Dosages & Sol

11th Edition

ISBN:9781305143531

Author:CURREN

Publisher:CURREN

Chapter10: Reconstitution Of Powdered Drugs

Section: Chapter Questions

Problem 7.8P

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Time point (min) Absorbance of culture at 660nm Approximate cell concentration Approximate # cells in 1mL extract 0 0.298 1.49 x 108 cells/mL 1.49 x 108 cells 10 0.316 1.58 x 108 cells/mL 1.58 x 108 cells 20 0.374 1.87 x 108 cells/mL 1.87 x 108 cells 30 0.429 2.145 x 108 cells/mL 2.145 x 108 cells 40 0.512 2.56 x 108 cells/mL 2.56 x 108 cells 50 0.544 2.72 x 108 cells/mL 2.72 x 108 cells 60 0.607 3.035 x 108 cells/mL 3.035 x 108 cells a. Using these data, prepare a growth curve of this strain ofEscherichia coli (E. coli).b. Estimate the doubling time for this strain of E. Coli. Clearly showhow you estimated this value from the empirical data presented.
Calculate the estimated concentration of test agent that inhibit cell growth by 50% ( GI50) value
Content X Content ✗ Ontariol × Content X Enteric- ChatGP × G Intrader × W Cold An X G The grad × + ☑ ← >> https://ontariolearn.blackboard.com/ultra/courses/_30758_1/cl/outline?legacyUrl=~2Fwebapps~2Fblackboard~2Fcontent~2Flaunch...✰ S Relaunch to update : M Gmail ►▸ YouTube Maps Sign in | Permanent... Search Results login... G My Grammarly - Gr... York Region Childre... Applications Home | bartleby (50,482 unread) - a... E อ Priva Tern Acce Remaining Time: 04 minutes, 52 seconds. * Question Completion Status: Ferrous gluconate is used as an iron supplement to treat and prevent iron-deficiency anemia. This medication is available with a strength of 300 mg per tablet. Your patient has been prescribed a dose of 0.45 g. Which of the following configurations will yield the correct answer to the dosage calculation? ○ 0.45 g 1 1 tab ✗ ✗ 300 mg 1000 mg 1 g 0.45 g 1 tab 1 g ✗ ✗ 1 300 mg 1000 mg 1 1 tab 1 g ✗ 0.45 g 300 mg 1000 mg ○ 0.45 g 1 300 mg 1 tab 1000 mg 1 g Click Save and Submit to save…
46 50 52 60 41 46 55 Find the ff. WITH SOLUTION PLEASE MeanMedianModeSDVarianceCVQuartile 2Decile 7Percentile 25Percentile 30
Content × Content / Ana ☑ OntarioLearn × Content × Furosemide is ☑ ChatGPT × G Intradermal in × + ☑ ← >> https://ontariolearn.blackboard.com/ultra/courses/_30758_1/cl/outline?legacyUrl=~2Fwebapps~2Fblackboard~2Fcontent~2Flaunch...✰ S Relaunch to update : M Gmail ►▸ YouTube Maps Sign in | Permanent... Search Results login... GMy Grammarly - Gr... York Region Childre... Applications Home | bartleby (50,482 unread) - a... Remaining Time: 13 minutes, 18 seconds. * Question Completion Status: 1 points ✓ Saved QUESTION 6 Furosemide is a loop diuretic used in the treatment of edema and hypertension. It is available with a strength of 20 mg/tab. A prescriber has ordered a daily dose of 40 mg. Which of the following configurations will yield the correct answer to the dosage calculation? 40mg 1 20 mg ✗ 1 tab ○ 40mg 1 tab 1 20 mg E 1 1 tab ✗ 40mg 20 mg อ 1 40mg 20 mg ✗ 1 tab Priva Tern Acce 1 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Q Search myhp W…
Serial dilution = previous dilution x dilution 11 mL [2] 3 mL Colony count: 100 0.1 mL sample [1] 9.9 mL 5 mL 0.1 ml. Cokony count Dilution: 10-1 10-3 [3] 150 Dilution factor (DF): [4] [5] [6] Compute for the CFU/mL of the sample. Show your solution and express your final answer to 2 significant figures.
a)Determine the amount of X (in gram) in order to prepare 100 mL of 50 mM stock solution of X. Show your work. (MW of X= 225) b)Determine the volume required (mL) from the stock solution X in (i) to prepare 500 mL of MS medium containing 5 mg/L X. Show your work.
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volume of the quasi-steady-state culture was V0= 500 L, and the nutrient solution containing glucose was added at a constant flow rate of F = 50 L/h.Data: X0 (at the beginning of feeding) = 20 g/L, S0 = 300 g/L, max = 0.2 h-1, KS = 0.5 g/L and Y x/s= 0.3 g/g a) Determine the volume of the culture at t = 10hb) Determine the concentration of glucose at t = 10 hc) determine the concentration and total mass of cells at t = 10 hd) If product is associated with growth with α = 1.5 and P0 = 0.1 g/L, determine the concentration of product at t = 10h. (answer:P = 67,55 g/L)
Table 1 - Comparison of the effect of catechol concentration on the amount of product formed. Absorbance Potato extract Absorbance 0 mins after 30mins (2nd reading) (mL) 1st reading 1 Tube # la blank 2a 3a 4a 1 1 1 dH₂O Catechol (mL) (mL) 7 5 3 1 0 2 4 6 0.00 0.060 0.033 0-05-2 Q4) Give 2 reasons for adding dH₂O to these tubes in Table 1? Time for reading: 3:21 -0.11 Absorbance: Time for reading: 3.36 Q5) Tube la serves as a control, but why is this control needed? Absorbance: 0.197 Time for reading: 3.37 Based on the data from Table 1 answer these questions: Q1) What is the name of the enzyme found in potato extract? Answer: catechol Q2) What is the substrate? Answer: THO Q3) Name of product of this enzyme catalyzed reaction? Answer: Absorbance: 0.152 Time for reading: 3:39 Absorbance: . 166 ness Catechol Benzoquinone Subtract 1st from 2nd reading -0.01 0-137 0.11.19 0.119 Q6) Notice that your 1st absorbance reading in tubes 2a-4a are quite similar but it then becomes very different…
HW....... Q1/: Compare the contact time necessary to obtain 99.99% kill of bacteria in water under the following conditions: 1- Free iodine residual of 0.45 mg/L and k=1.1* 10²/s. 2- Combined iodine residual of 8 mg/L with k= 1.2* 10²/s.
Please answer 1 and 2