Determine the fallowing:1. Rmax2. Euler's buckling stress3. Critical buckling stress4. Allowable compression stress5. Ultimate compression stress 280x85A = 7420 mm ²d=252 mmbf = 203 mmtf = 13.5mmtw = 8mm1x=87·10×106 mm²ly = 18.7x106mm²→→PL12x254The column shown is hinged @ the and fixed@ the bottom with an unsupported lengthequal to 12 mts. it has a lateral support 3meters from the bottom support, about theweater axis. Use Fy = 345 "Mpa"

A= 7420 mm d=252 mm bf = 203 mm tf = 13.5mm tw = 8mm 1x=87·10×106 mm²4 ly = 18.7*10% mm² →→PL 12x254 The column shown is hinged @ the and fixed @ the bottom with an unsupported length equal to 12 mts. It has a lateral support 3 meters from the bottom support, about the weater axis. Use Fy = 345 "Mpa"

A= 7420 mm d=252 mm bf = 203 mm tf = 13.5mm tw = 8mm 1x=87·10×106 mm²4 ly = 18.7*10% mm² →→PL 12x254 The column shown is hinged @ the and fixed @ the bottom with an unsupported length equal to 12 mts. It has a lateral support 3 meters from the bottom support, about the weater axis. Use Fy = 345 "Mpa"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

Determine the fallowing: 1. Rmax 2. Euler's buckling stress 3. Critical buckling stress 4. Allowable compression stress 5. Ultimate compression stress

280x85
A = 7420 mm ²
d=252 mm
bf = 203 mm
tf = 13.5mm
tw = 8mm
1x=87·10×106 mm²
ly = 18.7x106mm²
→→PL12x254
The column shown is hinged @ the and fixed
@ the bottom with an unsupported length
equal to 12 mts. it has a lateral support 3
meters from the bottom support, about the
weater axis. Use Fy = 345 "Mpa"

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Step 1: Introducing given data

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Step 2: Calculation of Moment of Inertia

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Step 3: Calculation of effective length (Le)

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Step 4: Determination of max slenderness ratio

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Step 5: Calculation of Euler's buckling stress & Critical buckling stress (Fcr)

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Step 6: Calculation of Allowable compressive strength & Ultimate compressive strength

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