A 4,500 ft, 13 3 /r-in. (ID = 12.615in.) casing string 171 is to be cemented in a 4, 530ft, -in. hole. The mud 2 weight is 10.01-al. The 1, 500ft tail slurry is 14.21º-al g g Class A cement with 4% bentonite. The remaining lead b slurry is 12.01-al Class A cement with 18% bentonite. g Use a 20% volumetric washout factor and 20bbl of brine as a pre-flush. Float collar is 40ft above casing shoe. Compute: Cement, water, and gel requirements. Displacement volume Differential pressure before releasing top plug Differential pressure when top plug lands on float collar A 4,500-ft, 13 %-in. (ID 12.615 in.) casing string is to be cemented in a 4,530 ft, 17%-in. hole. The mud weight is 10.0 lb/gal. The 1,500 ft tall slurry is 14.2 lb/gal Class A cement with 4% bentonite. The remaining lead slurry is 12.0 lb/gal Class A cement with 18% bentonite. Use a 20% volumetric washout factor and 20 bbl of brine as a pre-flush. Float collar is 40 ft above casing shoe. Compute: 1. Cement, water, and gel requirements. 2. Displacement volume 3. Differential pressure before releasing top plug 4. Differential pressure when top plug lands on float collar
A 4,500 ft, 13 3 /r-in. (ID = 12.615in.) casing string 171 is to be cemented in a 4, 530ft, -in. hole. The mud 2 weight is 10.01-al. The 1, 500ft tail slurry is 14.21º-al g g Class A cement with 4% bentonite. The remaining lead b slurry is 12.01-al Class A cement with 18% bentonite. g Use a 20% volumetric washout factor and 20bbl of brine as a pre-flush. Float collar is 40ft above casing shoe. Compute: Cement, water, and gel requirements. Displacement volume Differential pressure before releasing top plug Differential pressure when top plug lands on float collar A 4,500-ft, 13 %-in. (ID 12.615 in.) casing string is to be cemented in a 4,530 ft, 17%-in. hole. The mud weight is 10.0 lb/gal. The 1,500 ft tall slurry is 14.2 lb/gal Class A cement with 4% bentonite. The remaining lead slurry is 12.0 lb/gal Class A cement with 18% bentonite. Use a 20% volumetric washout factor and 20 bbl of brine as a pre-flush. Float collar is 40 ft above casing shoe. Compute: 1. Cement, water, and gel requirements. 2. Displacement volume 3. Differential pressure before releasing top plug 4. Differential pressure when top plug lands on float collar
Principles Of Marketing
17th Edition
ISBN:9780134492513
Author:Kotler, Philip, Armstrong, Gary (gary M.)
Publisher:Kotler, Philip, Armstrong, Gary (gary M.)
Chapter1: Marketing: Creating Customer Value And Engagement
Section: Chapter Questions
Problem 1.1DQ
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Transcribed Image Text:A 4,500 ft, 13 3 /r-in. (ID
=
12.615in.) casing string
171
is to be cemented in a 4, 530ft,
-in. hole. The mud
2
weight is 10.01-al. The 1, 500ft tail slurry is 14.21º-al
g
g
Class A cement with 4% bentonite. The remaining lead
b
slurry is 12.01-al Class A cement with 18% bentonite.
g
Use a 20% volumetric washout factor and 20bbl of brine
as a pre-flush. Float collar is 40ft above casing shoe.
Compute: Cement, water, and gel requirements.
Displacement volume Differential pressure before
releasing top plug Differential pressure when top plug
lands on float collar
A 4,500-ft, 13 %-in. (ID 12.615 in.) casing string is to be cemented in a 4,530 ft, 17%-in. hole. The mud weight is 10.0 lb/gal. The 1,500 ft tall
slurry is 14.2 lb/gal Class A cement with 4% bentonite. The remaining lead slurry is 12.0 lb/gal Class A cement with 18% bentonite. Use a 20%
volumetric washout factor and 20 bbl of brine as a pre-flush. Float collar is 40 ft above casing shoe. Compute:
1. Cement, water, and gel requirements.
2. Displacement volume
3. Differential pressure before releasing top plug
4. Differential pressure when top plug lands on float collar
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