A +4.2 percent grade intersects a -3.1 percent grade at station 52+41.34 (i.e. the PVIstation) at an elevation of 327.50 ft (i.e. the PVI elevation). The curve is 650 ft long.Calculate the centerline elevations for every 100-ft station (i.e. 51+00, 52+00, 53+00,etc.). Calculate the station and centerline elevations for the PVC, PVT, and low/highpoint on the curve. Sketch the curve; be sure to label the PVC, PVI, and PVT. Is this asag or crest curve?

Answered: A +4.2 percent grade intersects a -3.1…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20
A +2.5% grade meets a -1.75% grade at the station 44+25 and elevation 386.96 ft, the length of curve is 800 feet (8 stations). (1) Provide the stakeout for full stations using parabolic method STATION X g1 X (g2-g1) X2 2L Y (Elevation) PVT = PVC = (2) Determine the station and elevation at the high point of the curve
The curve elevation at station 20+00 is VC 1, PVI=21+72.41, PVI Elevation= 430.00 ft, L= 800 ft -3.20% -4.00% +1.50% VC 2, PVI 35+00 O 432.96 ft O 434.00 ft O 435.52 ft O 437.04 ft
mple: A-2.5% grade is connected to a +1.0% grade by means of a 180 m vertical curve. The P.I. station is 100 + 00 and the P.I. elevation is 100.0 m above sea level. What are the station and elevation of the lowest point on the vertical curve?
A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve, stakeout at half stations. Determine the elevation at the low point of the curve.
A plus 2.8% grade elevation intersects a minus 5.1% grade at station 2 + 087.224 at an elevation of 193.180 m. Calculate the elevations at every 20-m station for a 150-m vertical curve. (Please show solution for each station)
Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements shown below. A -3.40% grade meets a +2.75% grade at station 95+00 and elevation 1320.64 ft. Length of first curve 400 ft., second curve 600 ft. Match the correct elevation to the appropriate Station Value. Group of answer choices Sta. 91+00 (BVC) [ Choose ] Sta. 92+00 [ Choose ] Sta. 93+00 [ Choose ] Sta. 94+00 [ Choose
A spiral 80m long connects a tangent with a 7° 30' circular curve. If the stationing of the T.S. is 10+000, and the gauge of the tract on the curve is 1.5m. Determine the following: (a) the elevation of the outer rail at the midpoint, if the velocity of the fastest train that can pass over the curve is 60kph, (b) the spiral angle at the first quarter point, (c) the deflection angle at the end point, and (d) the offset from the tangent at the second quarter point.
Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation= 457.25 ft, compute the elevations of the curve low point and the 100 ft stations (meansstations 124+00, 125+00, etc. until reaching the end of the curve) as well as for the beginningand end of the curve.
A +5.1 percent grade intersects a -2.8 percent grade at station 68+70 at an elevation of 327.50 ft. Calculate the centerline elevations for the PVC, PVT, and every even 100-ft station for a 500-ft vertical curve.
A -3.00% grade meets a +2.50% grade at station 4 + 200 and elevation 105.568 m, 200-m curve, stakeout at 30-m increments.
PVI station and elevation are 326+00 and 841 ft. Incoming and outgoing grades are -2.50% and +3.00%. What is the curve length if it must pass through an elevation of 847 ft at station 327+50?

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