A +4.2 percent grade intersects a -3.1 percent grade at station 52+41.34 (i.e. the PVIstation) at an elevation of 327.50 ft (i.e. the PVI elevation). The curve is 650 ft long.Calculate the centerline elevations for every 100-ft station (i.e. 51+00, 52+00, 53+00,etc.). Calculate the station and centerline elevations for the PVC, PVT, and low/highpoint on the curve. Sketch the curve; be sure to label the PVC, PVI, and PVT. Is this asag or crest curve?

Answered: A +4.2 percent grade intersects a -3.1…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of 320.40 ft. Given that a 180-ft length of curve. The station of the PVC is A. 2+30 B. 3+30 C . 4+30 D. 5+30
2.) A 9% grade meets a 5% grade at station 2 + 270 of elevation 150 m. The lengths are L1 = 80 m. and L2 = 60 m. Calculate the elevation at PC, PT and at every full station.
An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20
A -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answer
A +2.5% grade meets a -1.75% grade at the station 44+25 and elevation 386.96 ft, the length of curve is 800 feet (8 stations). (1) Provide the stakeout for full stations using parabolic method STATION X g1 X (g2-g1) X2 2L Y (Elevation) PVT = PVC = (2) Determine the station and elevation at the high point of the curve
The curve elevation at station 20+00 is VC 1, PVI=21+72.41, PVI Elevation= 430.00 ft, L= 800 ft -3.20% -4.00% +1.50% VC 2, PVI 35+00 O 432.96 ft O 434.00 ft O 435.52 ft O 437.04 ft
mple: A-2.5% grade is connected to a +1.0% grade by means of a 180 m vertical curve. The P.I. station is 100 + 00 and the P.I. elevation is 100.0 m above sea level. What are the station and elevation of the lowest point on the vertical curve?
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A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve, stakeout at half stations. Determine the elevation at the low point of the curve.
A plus 2.8% grade elevation intersects a minus 5.1% grade at station 2 + 087.224 at an elevation of 193.180 m. Calculate the elevations at every 20-m station for a 150-m vertical curve. (Please show solution for each station)
A parabolic curve has a descending grade of -0.8% and an ascending grade of +0.4% that intersect at station 10 + 020 with an elevation of 240.600 m. If the maximum allowable rate of change of grade for this curve is 0.15% per 20 m stations, determine the following: A. The elevation at station 10 + 000 *Draw the figure
A-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located?

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