A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+-EDTA complex is 10.65 and the fraction of free EDTA in the Y“- form, ays-, is 0.041 at pH 9.00. What is K', the conditional formation constant, for Ca²+ at pH 9.00? K{ = 1.83 x10° What is the equivalence point volume, Ve, in milliliters? Ve = 132 mL Incorrect Calculate the concentration of Ca²+ at V = }Ve. [Ca²+] = 5.6 x10-9 M Incorrect Calculate the concentration of Ca²+ at V = V.. [Ca2+] = | 0.0133 M Incorrect Calculate the concentration of Ca²+ at V = 1.1V. [Ca2+] = | 0.0200 M Incorrect
A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+-EDTA complex is 10.65 and the fraction of free EDTA in the Y“- form, ays-, is 0.041 at pH 9.00. What is K', the conditional formation constant, for Ca²+ at pH 9.00? K{ = 1.83 x10° What is the equivalence point volume, Ve, in milliliters? Ve = 132 mL Incorrect Calculate the concentration of Ca²+ at V = }Ve. [Ca²+] = 5.6 x10-9 M Incorrect Calculate the concentration of Ca²+ at V = V.. [Ca2+] = | 0.0133 M Incorrect Calculate the concentration of Ca²+ at V = 1.1V. [Ca2+] = | 0.0200 M Incorrect
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+–EDTA
complex is 10.65 and the fraction of free EDTA in the Y form, ays-, is 0.041 at pH 9.00.
What is K, the conditional formation constant, for Ca²+ at pH 9.00?
K = 1.83 x10°
What is the equivalence point volume, Ve, in milliliters?
Ve = 132
mL
Incorrect
Calculate the concentration of Ca2+ at V =
[Ca2+] = | 5.6 x10-9
M
Incorrect
Calculate the concentration of Ca2+ at V = Ve.
[Ca?+] = 0.0133
M
Incorrect
Calculate the concentration of Ca²+ at V = 1.1Ve.
[Ca?+] = 0.0200
M
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b38345e-5e4f-4b50-8b7a-fe80fa164e76%2F6b4cd52b-b3e6-42e7-978f-be5a4d8ca647%2F9q51zhs_processed.png&w=3840&q=75)
Transcribed Image Text:A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+–EDTA
complex is 10.65 and the fraction of free EDTA in the Y form, ays-, is 0.041 at pH 9.00.
What is K, the conditional formation constant, for Ca²+ at pH 9.00?
K = 1.83 x10°
What is the equivalence point volume, Ve, in milliliters?
Ve = 132
mL
Incorrect
Calculate the concentration of Ca2+ at V =
[Ca2+] = | 5.6 x10-9
M
Incorrect
Calculate the concentration of Ca2+ at V = Ve.
[Ca?+] = 0.0133
M
Incorrect
Calculate the concentration of Ca²+ at V = 1.1Ve.
[Ca?+] = 0.0200
M
Incorrect
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