A 1.000 mL aliquot of a solution containing Cu2t and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. Thesolution is then back titrated with 0.02082 M Zn+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was neededto reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2+ and Ni2+ solution is fed through an ion-exchange columnthat retains Ni²+. The Cu2+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solutionrequired 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of0.05220 M EDTA.How many milliliters of 0.02082 M Zn2+ is required for the back titration of the Ni2+ solution?volume:mL

Given that : Volume of solution=1.000 mLVolume of EDTA = 25.00 mLMolarity of EDTA=0.05220 MMolarity…

A 1.000 mL aliquot of a solution containing Cu2+ and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. The solution is then back titrated with 0.02082 M Zn2+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2t and Ni2+ solution is fed through an ion-exchange column that retains Ni+. The Cu+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solution required 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of 0.05220 M EDTA. How many milliliters of 0.02082 M Zn+ is required for the back titration of the Ni2+ solution? volume: mL

A 1.000 mL aliquot of a solution containing Cu2+ and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. The solution is then back titrated with 0.02082 M Zn2+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2t and Ni2+ solution is fed through an ion-exchange column that retains Ni+. The Cu+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solution required 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of 0.05220 M EDTA. How many milliliters of 0.02082 M Zn+ is required for the back titration of the Ni2+ solution? volume: mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A 1.000 mL aliquot of a solution containing Cu2t and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. The
solution is then back titrated with 0.02082 M Zn+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was needed
to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2+ and Ni2+ solution is fed through an ion-exchange column
that retains Ni²+. The Cu2+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solution
required 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of
0.05220 M EDTA.
How many milliliters of 0.02082 M Zn2+ is required for the back titration of the Ni2+ solution?
volume:
mL

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