A 1.000 ml aliquot of a solution containing Cu* and Ni* is treated with 25.00 mL of a 0.03468 M EDTA solution. The solution is then back titrated with 0.02308 M Zn* solution at a pH of 5. A volume of 20.28 ml. of the Zn solution was needed to reach the xylenol orange end point. A 2.000 ml aliquot of the Cu* and Ni* solution is fed through an ion- exchange column that retains Ni. The Cu+ that passed through the column is treated with 25.00 mL of 0.03468 M EDTA. This solution required 23.18 mL of 0.02308 M Zn* for back titration. The Ni?+ extracted from the column was treated witn 25.00 mL of 0.03468 M EDTA. How many milliliters of 0.02308 M Zn* is required for the back titration of the Ni+ solution?

A 1.000 ml aliquot of a solution containing Cu* and Ni* is treated with 25.00 mL of a 0.03468 M EDTA solution. The solution is then back titrated with 0.02308 M Zn* solution at a pH of 5. A volume of 20.28 ml. of the Zn solution was needed to reach the xylenol orange end point. A 2.000 ml aliquot of the Cu* and Ni* solution is fed through an ion- exchange column that retains Ni. The Cu+ that passed through the column is treated with 25.00 mL of 0.03468 M EDTA. This solution required 23.18 mL of 0.02308 M Zn* for back titration. The Ni?+ extracted from the column was treated witn 25.00 mL of 0.03468 M EDTA. How many milliliters of 0.02308 M Zn* is required for the back titration of the Ni+ solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03169 M EDTA solution. The solution is then back titrated with 0.02152 M Zn²+ solution at a pH of 5. A volume of 15.93 mL of the Zn²+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion-exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.03169 M EDTA. This solution required 15.86 mL of 0.02152 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.03169 M EDTA. How many milliliters of 0.02152 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL
2. Titration of Ca²+ and Mg²+ in a 50mL sample of hard water required 23.65mL of 0.01205M EDTA. A second 50mL aliquot was made strongly basic with NaOH to precipitate Mg2+ as Mg(OH)2. The supernatant liquid was titrated with 14.53mL of the EDTA solution. Calculate a. concentration in ppm of CaCO3 in the sample. b. concentration in ppm of MgCO3 in the sample.
A 50.00 ml aliquot of a solution containing Ca2+ and Mg2+ was buffered at pH 10 and titrated with 0.0418 M EDTA. The endpoint volume was 44.36 ml. A second aliquot of the same mixture was made strongly basic by the addition of NaOH – this causes the Mg2+ to precipitate as Mg(OH)2. The solution was then titrated with the 0.0418 M EDTA and the endpoint volume was found to be 30.02 ml. Calculate the molar concentration of Mg.
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A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.04333 M EDTA solution. The solution is then back titrated with 0.02071 M Zn²+ solution at a pH of 5. A volume of 20.01 mL of the Zn²+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion-exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.04333 M EDTA. This solution required 18.20 mL of 0.02071 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.04333 M EDTA. How many milliliters of 0.02071 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL
A 1.000 ml. aliquot of a solution containing Cu?* and Ni* is treated with 25.00 ml, of a 0.03468 M EDTA solution. The solution is then back titrated with 0.02308 M Znt solution at a pH of 5. A volume of 20.28 ml. of the Zn+ solution was needed to reach the xylenol orange end point. A 2.000 ml. aliquot of the Cu* and Ni* solution is fed through an ion- exchange column that retains Ni*. The Cu+ that passed through the column is treated with 25.00 ml. of 0.03468 M EDTA. This solution required 23.18 ml. of 0.02308 M Zn* for back titration. The Ni" extracted from the column was treated witn 25.00 mL of 0.03468 M EDTA. How many milliliters of 0.02308 M Zn?* is required for the back titration of the NP solution? volume: ml.
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