A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03703 M EDTA solution. The solution is then back titrated with 0.02138 M Zn²+ solution at a pH of 5. A volume of 22.13 mL of the Zn²+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion-exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.03703 M EDTA. This solution required 18.53 mL of 0.02138 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.03703 M EDTA. How many milliliters of 0.02138 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL

A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03703 M EDTA solution. The solution is then back titrated with 0.02138 M Zn²+ solution at a pH of 5. A volume of 22.13 mL of the Zn²+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion-exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.03703 M EDTA. This solution required 18.53 mL of 0.02138 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.03703 M EDTA. How many milliliters of 0.02138 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

A scientist is asked to prepare 10 mL of a buffer by mixing equal volumes of 0.01M Tris-HCl buffer set at pH 8.0 and 0.001M EDTA solution. What are the masses required to prepare this buffer?
How will 100mM Tris-Cl buffer be prepared?
50 mL of a solution of 0.0200 M Zn2+ will be titrated with 0.0100 M EDTA in 0.0100 M NH3 at pH 6.0. Ethylenediaminetetraacetic acid (EDTA) can be considered as a tetraprotic acid (H4Y). The stepwise acid dissociation constants are: K1 = 1.02 x 10-2, K2= 2.14 x 10-3, K3 = 6.92 x 10-7 and K4 = 5.50 x 10-11. The alplia value of the un-deprotonated species in a solution buffered to a certain pH is given by the following equation: a0 = [H+]4/([H+]4 + K1[H+]3 + K1K2[H+]2 + K1 K2K3[H+] + K1 K2K3K4) Calculate the alpha value of the fully deprotonated species (Y4- ) in a solution buffered to a pH of 6.0.
A solution containing 60 mL of a 0.025 mol / L metal ion (Mn +) buffer buffered to pH 7.0 was titrated with a 0.05 mol / L EDTA solution. Data: Conditional formation constant (Kf)=10^15. Determine: i) The concentration of the free metal when ½ of the equivalence volume is added. ii) the concentration of free metal in the equivalence volume. iii) the concentration of free metal with an excess of 2 mL of EDTA? (Data - EDTA constants: K1=0.01; K2=2.19.10^-3; K3=6.92.10^-7; K4=5.75.10^-11)
Calculate the resulting pH of the buffer solution when 18 mL of 398 mM HCl is added to 1 L of a 50 mM MOPS buffer at pH = 7.2. The pKa for the MOPS compound is 7.2. Assume negligible volume change upon the addition of the acid.
49.97 ml of 0.08726 M potassium oxalate buffered at pH 8.27 is titrated with 0.07172 M potassium permanganate. What is the potential after 39.47 mL of potasslum permanganate has been added? Report just the potential in volts; don't Include the units (Canvas is challenged).
The chemical formula for the oxalate ion is C2O42-. A liter of a saturated solution of calcium oxalate at 25 oC was evaporated to dryness, giving 0.0061 g of solid CaC2O4 residue. Calculate the solubility product constant for CaC2O4 at 25 oC.
A 50.00 mL aliquot of city drinking water was treated with a small amount of ammonia –- ammonium chloride buffer to bring the pH to 10. After the addition of EBT indicator the solution required 10.00 mL of 8.000 x 10-3 M EDTA for titration. Calculate the hardness in terms of parts per million calcium carbonate (100.0869 g/mol). O 80 160 ppm 320
Titration of 46.00 mL of 0.04726 M Na2 C2 04 required 39.26 mL of a potassium permanganate solution. 2Mn O4 + 5H2 C2O4 + 6H+ → 2MN²+ + 10CO2 (g) + 8H20 Calculate the molar concentration of the KMNO4 solution. Concentration
50 mL of a sample known to contain Mg+2 was taken and titrated with 0.075 M EDTA standard solution by adding pH 10 buffer and EBT indicator. Since the EDTA consumption is 10.5 mL, which of the following is the amount of magnesium in the sample in ppm? (Mg:24 B/mol)
The water hardness of tap water has been determined to be 120 (= 120 mg CaCO3 per 1 L of water). After the tap water has run through the ion exchange column, titration of a 20.00 mL sample used only 0.70 mL of 0.0100 M EDTA, to reach the endpoint. Calculate the effectiveness of the ion exchange column: what is the % of the calcium, removed by the ion exchange column? Provide your answer in % and without decimal. ( Please type answer note write by hend)
A titration of 50.00 mL of 0.1100 M Fe3+ with 0.07750 M Sn2+ is carried out. The analytical reaction is 2Fe3+ + Sn2+ ⇋ 2Fe2+ + Sn4+ and Fe3+ + e− ⇋ Fe2+ E° = +0.732 V Sn4+ + 2e− ⇋ Sn2+ E° = +0.139 V What is the volume of Sn2+ is added at the equivalence point?