A soil was measured for cation exchange by leaching 15 g of soil with 80 mL of solution of 1 M ammonium (NH4*) acetate solution buffered at pH 7. The leachate solution was analyzed and found to have 115 mg/L of Ca and 52 mg/L of Mg. The molecular weights are: Ca = 40.1 g/mol; Mg = 24.3 g/mol. 1 mole = 0.01 centimoles. (Watch unit conversions and significant figures!) (a) Calculate the equivalent moles of charge per kg of soil contributed by each cation (Ca and Mg) expressed as centimoles of charge per kilogram of soil (cmol, kgʻ1).

A soil was measured for cation exchange by leaching 15 g of soil with 80 mL of solution of 1 M ammonium (NH4*) acetate solution buffered at pH 7. The leachate solution was analyzed and found to have 115 mg/L of Ca and 52 mg/L of Mg. The molecular weights are: Ca = 40.1 g/mol; Mg = 24.3 g/mol. 1 mole = 0.01 centimoles. (Watch unit conversions and significant figures!) (a) Calculate the equivalent moles of charge per kg of soil contributed by each cation (Ca and Mg) expressed as centimoles of charge per kilogram of soil (cmol, kgʻ1).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

D10)

A soil was measured for cation exchange by leaching 15 g of soil with 80 mL of
solution of 1 M ammonium (NH4*) acetate solution buffered at pH 7. The
leachate solution was analyzed and found to have 115 mg/L of Ca and 52 mg/L
of Mg.
The molecular weights are: Ca = 40.1 g/mol; Mg = 24.3 g/mol. 1 mole = 0.01
centimoles. (Watch unit conversions and significant figures!)
(a) Calculate the equivalent moles of charge per kg of soil contributed by each
cation (Ca and Mg) expressed as centimoles of charge per kilogram of soil
(cmol, kgʻ1).

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