Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Mn→ Mn2+ + 2e
Mn2+
Mn³+ + e
Mn3+ + 2H₂O → MnO2 + 4H+ + e
MnO2 + 2H₂O → MnO42- + 4H+ + 2e-
MnO42- MnO4 + e
Mn2+ + 2H₂O → MnO2 + 4H+ 2e
Eº = -1.23 V
MnO2 + 2H2O → MnO4 + 4H+ + 3e
Eº = -1.70 V
Mn2+ + 4H20 MnO4 + 8H+ + 5e
EO = -1.51 V
-
i. Summarise the above potential data by means of a Latimer and Frost diage
EO = +1.18 V
Eº = -1.51 V
EO = -0.95 V
EO = -2.26 V
Eº = -0.56 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93ef1671-3d5f-4e53-b55b-3862b98d6cda%2F12ef6de7-daf1-4abe-8946-51f07960373f%2Farcia2k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Mn→ Mn2+ + 2e
Mn2+
Mn³+ + e
Mn3+ + 2H₂O → MnO2 + 4H+ + e
MnO2 + 2H₂O → MnO42- + 4H+ + 2e-
MnO42- MnO4 + e
Mn2+ + 2H₂O → MnO2 + 4H+ 2e
Eº = -1.23 V
MnO2 + 2H2O → MnO4 + 4H+ + 3e
Eº = -1.70 V
Mn2+ + 4H20 MnO4 + 8H+ + 5e
EO = -1.51 V
-
i. Summarise the above potential data by means of a Latimer and Frost diage
EO = +1.18 V
Eº = -1.51 V
EO = -0.95 V
EO = -2.26 V
Eº = -0.56 V
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