7. Suppose a 25.0 kg block rests on a horizontal plane, and the static friction coefficient between the surfaces is 0.220. (a) What is the maximum allowable static frictional force that could act on the block? (b) What is the actual static frictional force acting on the block if a 25.0 N external force acts horizontally? Assume g = 9.80 m/s.
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- Many birds can attain very high speeds when diving. Using radar, scientists measured the altitude of a barn swallow in a vertical dive; it dropped 208 m in 3.0 s. The mass of the swallow was estimated to be 0.018 kg, and its cross-section area as 5.6 x 10-4 m2. What was the drag coefficient for this swallow as it dove?Determine two force members first. Two blocks are each pin connected to a massless horizontal link. Determine the largest P before motion cocurs. Use 0.35 and 0.3 for the friction coefficients. 45° J c 4.5 kg 3 kg B 30°A 1500-N crate is to be held in place on a ramp that rises at 30.0° above the horizontal (see figure). The massless rope attached to the crate makes a 22.0° angle above the surface of the ramp. The coefficients of friction between the crate and the surface of the ramp are uk = 0.450 and us = 0.650. The pulley has no appreciable mass or friction. What is the MAXIMUM weight w that can be used to hold this crate stationary on the ramp? %3D W= ? Crate 22.0° Ramp 30.00
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- A 78 kg crate rests on a rough horizontal surface. The coefficient of static friction and coefficient of kinetic friction are 0.3 and 0.2, respectively. What would happen if the applied horizontal force is 300 N? Choices: It will remain at rest. The frictional force will be neglected. It will accelerate in the same direction as the horizontal force. It will accelerate in the opposite direction as the horizontal force.The 118-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume ??= 0.48, ??= 0.38.