A constant applied force F, of 15.0 N pushes a box with a mass m = 7.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Fp m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf m/s If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? Fnew = N
A constant applied force F, of 15.0 N pushes a box with a mass m = 7.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Fp m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf m/s If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? Fnew = N
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A constant applied force ? of 15.0 N pushes a box with a mass ?=7.00 kg a distance ?=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150.
![A constant applied force \( F_p \) of 15.0 N pushes a box with a mass \( m = 7.00 \, \text{kg} \) a distance \( x = 15.0 \, \text{m} \) across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150.
**Diagram Explanation:**
- The diagram shows a box of mass \( m \) on a horizontal surface.
- An arrow labeled \( F_p \) indicates a force pushing the box to the right.
- The horizontal distance \( x \) is marked with a double-headed arrow above the box, representing the displacement.
**Questions:**
1. Assuming that the box starts from rest, what is the final velocity \( v_f \) of the box at the 15.0 m point?
\( v_f = \) [space for answer] m/s
2. If there were no friction between the box and the floor, what applied force \( F_{\text{new}} \) would give the box the same final velocity?
\( F_{\text{new}} = \) [space for answer] N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff90e9f76-a8ee-4e86-857e-4cb9f0bb2381%2F4cc428ed-52a6-40e9-93b8-908a16dbc153%2Fkdcnt25_processed.png&w=3840&q=75)
Transcribed Image Text:A constant applied force \( F_p \) of 15.0 N pushes a box with a mass \( m = 7.00 \, \text{kg} \) a distance \( x = 15.0 \, \text{m} \) across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150.
**Diagram Explanation:**
- The diagram shows a box of mass \( m \) on a horizontal surface.
- An arrow labeled \( F_p \) indicates a force pushing the box to the right.
- The horizontal distance \( x \) is marked with a double-headed arrow above the box, representing the displacement.
**Questions:**
1. Assuming that the box starts from rest, what is the final velocity \( v_f \) of the box at the 15.0 m point?
\( v_f = \) [space for answer] m/s
2. If there were no friction between the box and the floor, what applied force \( F_{\text{new}} \) would give the box the same final velocity?
\( F_{\text{new}} = \) [space for answer] N
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