lock A in the figure weighs 60.0 The coefficient of static friction between the block and the surface on which it 45.0 rests is 0.25. The weight w is 12.0 N and the system is in equilibrium. Find the friction force exerted on block A. (b) Find the maximum weight w for which the system will remain in equilibrium.
lock A in the figure weighs 60.0 The coefficient of static friction between the block and the surface on which it 45.0 rests is 0.25. The weight w is 12.0 N and the system is in equilibrium. Find the friction force exerted on block A. (b) Find the maximum weight w for which the system will remain in equilibrium.
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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Transcribed Image Text:**Problem Statement:**
3. (a) Block A in the figure weighs 60.0 N. The coefficient of static friction between the block and the surface on which it rests is 0.25. The weight \( w \) is 12.0 N and the system is in equilibrium. Find the friction force exerted on block A.
(b) Find the maximum weight \( w \) for which the system will remain in equilibrium.
**Diagram Explanation:**
The diagram illustrates a system where Block A is placed on a horizontal surface. Block A is connected by a rope over a pulley to another weight \( w \). The rope is oriented at an angle of 45.0° with the vertical. The system is in equilibrium, which means that the forces acting on both Block A and the weight \( w \) are balanced.
**Detailed Analysis:**
- The force diagram includes:
- Weight of Block A: 60.0 N acting downward.
- Static friction force acting backward (opposite to potential movement).
- Normal force exerted by the surface on Block A, acting upward.
- Tension in the rope, which is directed at a 45° angle from the vertical.
- The force analysis should consider both the vertical and horizontal components of forces due to the pulley system arrangement.
This setup allows for the calculation of both the current friction force and the maximum weight \( w \) that can be supported without initiating motion, based on the static friction limit.
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