5.4 Give the Vmax and Km for this enzyme that obeys Michaelis-Menten kinetics. Use 2 sig figs. 0.6 y = 0.5032x + 0.0516 0.5 0.4 0.3 0.2 0.1 -0.4 -0.2 0.2 0.4 0.6 0.8 1 -0.1 1/[S] (mM) 1/v (mmol/sec)
5.4 Give the Vmax and Km for this enzyme that obeys Michaelis-Menten kinetics. Use 2 sig figs. 0.6 y = 0.5032x + 0.0516 0.5 0.4 0.3 0.2 0.1 -0.4 -0.2 0.2 0.4 0.6 0.8 1 -0.1 1/[S] (mM) 1/v (mmol/sec)
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Give the Vmax and Km for this enzyme that obeys Michaelis-Menten kinetics. Use 2 sig figs.
![The given image is a Lineweaver-Burk plot, which is used to determine the kinetic parameters of an enzyme that follows Michaelis-Menten kinetics. The graph is a double-reciprocal plot where the y-axis represents \( \frac{1}{v} \) (inverse of reaction velocity in mmol/sec) and the x-axis represents \( \frac{1}{[S]} \) (inverse of substrate concentration in mM).
The equation of the line is given as:
\[ y = 0.5032x + 0.0516 \]
This equation is in the form of a straight line \( y = mx + b \), where:
- \( m \) (slope) = 0.5032
- \( b \) (y-intercept) = 0.0516
To find the maximum velocity (\( V_{max} \)) and the Michaelis constant (\( K_m \)):
- \( V_{max} \) is the reciprocal of the y-intercept (\( b \)):
\[ V_{max} = \frac{1}{0.0516} \]
- \( K_m \) can be calculated using the slope (\( m \)) and \( V_{max} \):
\[ K_m = \text{slope} \times V_{max} = 0.5032 \times V_{max} \]
These calculations will give the values of \( V_{max} \) and \( K_m \) with two significant figures.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5410df3-c9ca-4567-8ddf-095cfca5a016%2Faca742b9-cd7a-49ca-9e48-0d181902f302%2Foe20gpt_processed.png&w=3840&q=75)
Transcribed Image Text:The given image is a Lineweaver-Burk plot, which is used to determine the kinetic parameters of an enzyme that follows Michaelis-Menten kinetics. The graph is a double-reciprocal plot where the y-axis represents \( \frac{1}{v} \) (inverse of reaction velocity in mmol/sec) and the x-axis represents \( \frac{1}{[S]} \) (inverse of substrate concentration in mM).
The equation of the line is given as:
\[ y = 0.5032x + 0.0516 \]
This equation is in the form of a straight line \( y = mx + b \), where:
- \( m \) (slope) = 0.5032
- \( b \) (y-intercept) = 0.0516
To find the maximum velocity (\( V_{max} \)) and the Michaelis constant (\( K_m \)):
- \( V_{max} \) is the reciprocal of the y-intercept (\( b \)):
\[ V_{max} = \frac{1}{0.0516} \]
- \( K_m \) can be calculated using the slope (\( m \)) and \( V_{max} \):
\[ K_m = \text{slope} \times V_{max} = 0.5032 \times V_{max} \]
These calculations will give the values of \( V_{max} \) and \( K_m \) with two significant figures.
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