The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate Vo for an enzyme-catalyzed, single-substrate reaction E + SES → E + P. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and [S] >> Km. Match each statement with the condition that it describes. Note that "rate" refers to initial velocity Vo where steady state conditions are assumed. [Etotal] refers to the total enzyme concentration and [Efree] refers to the concentration of free enzyme. [S] << Km [ES] is much lower than [Efree]. Almost all active sites will be filled. [S] = Km [Efree] is about equal to [Etotal]. The rate is half of the maximum rate. [S] >> Km This condition rarely occurs for most in vivo enzymes. Answer Bank Not true for any of these conditions Increasing [Etotal] will lower Km.

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The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate Vo for an
enzyme-catalyzed, single-substrate reaction E + SES → E + P. The model can be more readily understood when
comparing three conditions: [S] << Km, [S] = Km, and [S] >> Km.
Match each statement with the condition that it describes.
Note that "rate" refers to initial velocity Vo where steady state conditions are assumed. [Etotal] refers to the total enzyme
concentration and [Efree] refers to the concentration of free enzyme.
[S] << Km
[ES] is much lower than [Efree].
Almost all active sites will
be filled.
[S] = Km
[Efree] is about equal to [Etotal].
The rate is half of the
maximum rate.
[S] >> Km
This condition rarely occurs for
most in vivo enzymes.
Answer Bank
Not true for any of these
conditions
Increasing [Etotal] will lower Km.
Transcribed Image Text:The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate Vo for an enzyme-catalyzed, single-substrate reaction E + SES → E + P. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and [S] >> Km. Match each statement with the condition that it describes. Note that "rate" refers to initial velocity Vo where steady state conditions are assumed. [Etotal] refers to the total enzyme concentration and [Efree] refers to the concentration of free enzyme. [S] << Km [ES] is much lower than [Efree]. Almost all active sites will be filled. [S] = Km [Efree] is about equal to [Etotal]. The rate is half of the maximum rate. [S] >> Km This condition rarely occurs for most in vivo enzymes. Answer Bank Not true for any of these conditions Increasing [Etotal] will lower Km.
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