4. A subsurface exploration is conducted and it is discovered that the subsurface soils are primarily stiff sandy clays. Given the spacing of some of the columns it is decided that strip footings would best support them. The proposed footing configuration is shown below. Determine the ultimate loads that can be supported by the footing shown if it is founded at a depth of 3.5 feet below the ground surface. The groundwater was found to be at a depth of 10 ft below the ground surface. Assume the rectangular foundation is rigid and that the loads from both columns are uniformly supported by the footing. Use a factor of safety of 4. 15 ft
4. A subsurface exploration is conducted and it is discovered that the subsurface soils are primarily stiff sandy clays. Given the spacing of some of the columns it is decided that strip footings would best support them. The proposed footing configuration is shown below. Determine the ultimate loads that can be supported by the footing shown if it is founded at a depth of 3.5 feet below the ground surface. The groundwater was found to be at a depth of 10 ft below the ground surface. Assume the rectangular foundation is rigid and that the loads from both columns are uniformly supported by the footing. Use a factor of safety of 4. 15 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:4. A subsurface exploration is conducted and it is discovered that the subsurface soils are primarily
stiff sandy clays. Given the spacing of some of the columns it is decided that strip footings would best
support them. The proposed footing configuration is shown below. Detemine the ultimate loads that
can be supported by the footing shown if it is founded at a depth of 3.5 feet below the ground surface.
The groundwater was found to be at a depth of 10 ft below the ground surface. Assume the rectangular
foundation is rigid and that the loads from both columns are uniformly supported by the footing. Use
a factor of safety of 4.
15 ft
2.5 ft
2.5 ft
5 ft
10 ft
PLAN
Qult
Qult
ELEVATION
3.5 ft
14 in
C =
300 lb/ft?
10 ft
y = 118.6 lb/ft³
Ø = 15°
c = 300 lb/ft²
Ysat = 126.6 lb/ft³
Ø = 15°
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