0.03, eo A 1.5-m square, 0.5-m deep footing carries a downward service load of 180 kN. It is underlain by an overconsolidated clay (OC case II) with the following engineering properties: C = 0.15, C, 18.0 kN/m³ above the groundwater table and 20.0 kN/m³ below. The groundwater table is at a depth of 6.0 m below the ground surface. The clay is 8 m thick from the base of footing. The pre-consolidation stress is 48 kPa. Determine the total settlement of this footing. = = 0.5, and y =

0.03, eo A 1.5-m square, 0.5-m deep footing carries a downward service load of 180 kN. It is underlain by an overconsolidated clay (OC case II) with the following engineering properties: C = 0.15, C, 18.0 kN/m³ above the groundwater table and 20.0 kN/m³ below. The groundwater table is at a depth of 6.0 m below the ground surface. The clay is 8 m thick from the base of footing. The pre-consolidation stress is 48 kPa. Determine the total settlement of this footing. = = 0.5, and y =

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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KINDLY GET THE RIGHT ANSWER Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are Cs = 1/5 Cc, Ꝺ’c= 40 kN/m2. Field monitoring indicated that the foundation settlement was 19 mm during the first 12 months. Estimate the coefficient of consolidation for the pressure range. Estimate the settlement in 24 months.
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A 650-kN column load is supported on a 1.5 m wide by 2.0 m long by 0.5 m deep spread foot-ing. The soil below is a well-graded, normally consolidated sand with g = 18.0 kN/m3 and the following SPT N60 values:Depth (m) 1.0 2.0 3.0 4.0 5.0N60 12 13 13 8 22 The groundwater table is at a depth of 25 m. Compute settlement of the footing using the gen-eralized elastic method with Christian and Carrier’s (1978) influence factors.
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