The specifications call for maximum allowable settlement of 25mm. Using the classical method calculate the settlement of the continuous footing shown in the figure and determine if the specification for settlement is satisfied 2.5 m 3.5 m 500 mm PD = 40 kN/m PL = 25 kN/m 1200 mm Silty Clay Ce/(1+e) = 0.13 Cr1+e)=0.04 Om=300 kPa Y= 18.0 kN/m³ Silty Clay Ce/(1+e) = 0.13 Cr/(1+e) = 0.04 Om = 10 kPa Y = 17.8 kN/m3 Clay C/(1+e) = 0.15 Cr/(1+e) = 0.05 0=400 kPa Y = 19.0 kN/m3 500 mm 1.0 m 1.0 m 1.5 m 2.0 m 3.0 m

The specifications call for maximum allowable settlement of 25mm. Using the classical method calculate the settlement of the continuous footing shown in the figure and determine if the specification for settlement is satisfied 2.5 m 3.5 m 500 mm PD = 40 kN/m PL = 25 kN/m 1200 mm Silty Clay Ce/(1+e) = 0.13 Cr1+e)=0.04 Om=300 kPa Y= 18.0 kN/m³ Silty Clay Ce/(1+e) = 0.13 Cr/(1+e) = 0.04 Om = 10 kPa Y = 17.8 kN/m3 Clay C/(1+e) = 0.15 Cr/(1+e) = 0.05 0=400 kPa Y = 19.0 kN/m3 500 mm 1.0 m 1.0 m 1.5 m 2.0 m 3.0 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

The specifications call for maximum allowable settlement of 25mm. Using the classical method calculate
the settlement of the continuous footing shown in the figure and determine if the specification for
settlement is satisfied
2.5 m
3.5 m
500 mm
PD = 40 kN/m
PL = 25 kN/m
1200 mm
Silty Clay
Ce/(1+e) = 0.13
CrR1+e)=0.04
Om=300 kPa
Y= 18.0 kN/m³
Silty Clay
Ce/(1+e) = 0.13
Cr/(1+e) = 0.04
Om = 10 kPa
Y = 17.8 kN/m3
Clay
C/(1+e) = 0.15
Cr/(1+e) = 0.05
Om = 400 kPa
Y = 19.0 kN/m3
500 mm
1.0m
1.0 m
1.5 m
2.0 m
3.0 m

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