(360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current value (I) is 0.1 times starting current (I). Motor is rotating with 1000 rpm value under full load conditions. Find the E, (reverse EMF), armature torque (Ta), armature power (Pa) values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2) values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.) EA= Ta= Pa= n2 Ta2=

(360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current value (I) is 0.1 times starting current (I). Motor is rotating with 1000 rpm value under full load conditions. Find the E, (reverse EMF), armature torque (Ta), armature power (Pa) values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2) values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.) EA= Ta= Pa= n2 Ta2=

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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600V, DC series motor operates at 600 rpm and rated load. Armature resistance 0.1 ohm and series fieldwinding resistance is 0.05 ohms. At full load, the motor draws 195 A current. A) Find the reverse(back) EMF value at full load. B) Find the power and internal moment produced in the armature under full load.
A 36 V DC motor is listed in a catalogue as having the following specifications when operated with rated voltage: • no-load speed: 3,200 rpm, stall torque: 12 Nm. Calculate the back-emf constant, the current under stall conditions, and hence the armature resistance.
A 230 volt d.c. motor withThe armature resistance of the motor is 0.6 ohm. If full load armature current is 50 A and no load armature current is 8 A. So find the change in back emf from no load to full load.
In a three-phase switched reluctance motor having six stator poles and four rotor poles, the pole widths for the stator and rotor poles are the same, with φs = φr = 40°. The currents in the phase windings are applied when the inductances are increasing. Draw qualitively the current and torque wave- forms of each phase and the total torque developed by the motor for a square wave current having. (a) 40° width. (b) 30° width. (c) 20° width.
power electronics and drives
360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line currentvalue (I) is 0.1 times starting current 1.). Motor is rotating with 1000 rpm value under full load conditions. Find the EA (reverse EMF), armature torque (Ta), armature power (Pa)values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2)values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.)EA=?Ta=?Pa=?n2 =?Ta2=?
Estimate the stator current, equivalent rotor current, efficiency, output, and its power factor at aslip of 5% for a motor having a following data: Stator impedance = 1.0 + j3.0 ohms, rotor standstill impedance 1.0 + j2.0 ohms, no-load shunt impedance = 10+ j50 ohms, volts/phase = 250 volts.
1. A DC series motor has a rated of 25 hp, 200V, 2 000 rpm, 4 poles, 800 conductors that arranged in simplex lap winding and an armature circuit resistance is 0.012. At rated power and rated speed, the motor draws a line current of 100A. A. Calculate the flux per pole when then motor run at rated speed. B. Calculate the armature torque value that develop at rotor shaft when operates at rated- load. C. Calculate the rotational losses when the motor operates at rated power. D. Calculate the total motor efficiency.
ELECTRICAL MACHINE (DC MOTOR)
(2-) 480 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 3 times of serial field circuit total resistance (Rs) for this motor. And full load line current value (IL) is 0.2 of times starting current (Ist). Motor is rotating with 1200 rpm value under full load conditions. Find the EA (reverse EMF) , armature torque (Ta) , armature power (Pa) values for this motor. If a starting resistance (Rst) is connected in serial with the serial field resistance (Rs) of the motor to limit the starting current to 20 A. Find the value of this resistance (Rst) and the input power (Pin) of the motor for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.
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Consider a shunt DC motor with an armature resistance RA =0.2N and terminal voltage VT = 160 V. The motor rated speed is 1800 RPM. The total field resistance 240 Q. Assume No armature reaction in this machine. The variation of the armature terminal voltage as a function of the field current is measured under no-load conditions and shown below: IF (A) EA (V) 1.0 141 0.0 0.6 125 These values were taken at speed n= 1800 RPM 0.1 0.2 0.3 0.4 0.5 0.7 0.8 0.9 30 60 85 102 115 132 137 140 If the motor is driving a load at an armature current IA=60 A, its rotational speed is 1517 RPM, with rotational losses of 848 Watt. What torque is induced by this motor? Select one: O a. Induced Torque = 62 N.m O b. Induced Torque = 56 N.m O c. None O d. Induced Torque = 51 N.m.