360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current value (I) is 0.1 times starting current 1.). Motor is rotating with 1000 rpm value under full load conditions. Find the EA (reverse EMF), armature torque (Ta), armature power (Pa) values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2) values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.) EA=? Ta=? Pa=? n2 =? Ta2=?

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360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current
value (I) is 0.1 times starting current 1.). Motor is rotating with 1000 rpm value under full load conditions. Find the EA (reverse EMF), armature torque (Ta), armature power (Pa)
values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2)
values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.)
EA=?
Ta=?
Pa=?
n2 =?
Ta2=?

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