A 240-V, 900 rpm DC series motor takes 25 A at full load. The armature resistance is 0.20 and the field-winding resistance is 0.3 Q. The rotational loss is 300 W. (i) Calculate (a) Power developed (b) torque developed (c) power output (d) available torque (e) copper loss (f) efficiency. (ii) Draw a labeled power flow diagram showing all the values of power flow. (iii) If an increase of 40% in the armature current results in a 15% increase in flux, determine the speed and torque developed when the motor operates at 40A.
A 240-V, 900 rpm DC series motor takes 25 A at full load. The armature resistance is 0.20 and the field-winding resistance is 0.3 Q. The rotational loss is 300 W. (i) Calculate (a) Power developed (b) torque developed (c) power output (d) available torque (e) copper loss (f) efficiency. (ii) Draw a labeled power flow diagram showing all the values of power flow. (iii) If an increase of 40% in the armature current results in a 15% increase in flux, determine the speed and torque developed when the motor operates at 40A.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:A 240-V, 900 rpm DC series motor takes 25 A at full load. The armature resistance is 0.20 and
the field-winding resistance is 0.3 Q. The rotational loss is 300 W.
(i) Calculate
(a) Power developed (b) torque developed (c) power output (d) available torque
(e) copper loss (f) efficiency.
(ii) Draw a labeled power flow diagram showing all the values of power flow.
(iii) If an increase of 40% in the armature current results in a 15% increase in flux, determine
the speed and torque developed when the motor operates at 40A.
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