A series DC motor has a series-field winding of 25 turns per pole. Its armature resistance is 0.15 0. and its field resistance is 0.05 0. When the motor is rotating at 900 RPM, with a 380 V DC supply, its current is 142 A. and rotational losses of 4500 Watt. Find the copper losses and the efficiency of this motor. Answers: Pcu- Watt, and %n - %.
A series DC motor has a series-field winding of 25 turns per pole. Its armature resistance is 0.15 0. and its field resistance is 0.05 0. When the motor is rotating at 900 RPM, with a 380 V DC supply, its current is 142 A. and rotational losses of 4500 Watt. Find the copper losses and the efficiency of this motor. Answers: Pcu- Watt, and %n - %.
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
Transcribed Image Text:A series DC motor has a series-field winding of 25 turns per pole. Its armature resistance is 0.15
0.
and its field resistance is 0.05 0.
When the motor is rotating at 900 RPM, with a 380 V DC supply, its current is 142 A,
and rotational losses of 4500 Watt.
Find the copper losses and the efficiency of this motor.
Answers:
Pcu =
Watt, and %n
%.
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