33. y+y+2y= 0, y(0) = y'(0) = 0 34. y" - 2y' + y = 0, y(0) = 5, y'(0) = 10 35. y + 12y" + 36y' = 0, y(0) = 0, y'(0) = 1, y"(0) = −7 36. y+2y5y' - 6y= 0, y(0) = y'(0) = 0, y"(0) = 1 In Problems 29-36 solve the given initial-value problem. 29. y + 16y0, y(0) = 2, y'(0) = -2 +y=0, y(π/3) = 0, y'(π/3) = 2 d²y 30. d²y dy 31. 4 5y = 0, y(1) 0, y'(1) = 2 dr² dt 32. 4y" -4y' -3y-0, y(0) -1, y'(0) - 5
33. y+y+2y= 0, y(0) = y'(0) = 0 34. y" - 2y' + y = 0, y(0) = 5, y'(0) = 10 35. y + 12y" + 36y' = 0, y(0) = 0, y'(0) = 1, y"(0) = −7 36. y+2y5y' - 6y= 0, y(0) = y'(0) = 0, y"(0) = 1 In Problems 29-36 solve the given initial-value problem. 29. y + 16y0, y(0) = 2, y'(0) = -2 +y=0, y(π/3) = 0, y'(π/3) = 2 d²y 30. d²y dy 31. 4 5y = 0, y(1) 0, y'(1) = 2 dr² dt 32. 4y" -4y' -3y-0, y(0) -1, y'(0) - 5
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
In Problems 29–36 solve the given initial-value problem
please solve problem 29 , 31,33 and 35 please

Transcribed Image Text:33. y+y+2y= 0, y(0) = y'(0) = 0
34. y" - 2y' + y = 0, y(0) = 5, y'(0) = 10
35. y + 12y" + 36y' = 0, y(0) = 0, y'(0) = 1, y"(0) = −7
36. y+2y5y' - 6y= 0, y(0) = y'(0) = 0, y"(0) = 1

Transcribed Image Text:In Problems 29-36 solve the given initial-value problem.
29. y + 16y0, y(0) = 2, y'(0) = -2
+y=0, y(π/3) = 0, y'(π/3) = 2
d²y
30.
d²y dy
31.
4
5y = 0, y(1) 0, y'(1) = 2
dr²
dt
32. 4y" -4y' -3y-0, y(0) -1, y'(0) - 5
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