3127. The NBS Tables of Chemical Thermodynamic Properties in the Journal of Physical &Chemical Reference Data, Vol. 11, 1982, p 252, report the following data:ESpΔΗAGkJ/molkJ/molJ/K-molKI2(aq)55.19-51.57111.3A12(aq)22.6 m 16.46137.2PI,(aq)51.5)-51.4239.3a. Using the data in the table, use Hess's law to calculate thetriiodide formation.12 (99) +1 (99) → 15 (ad)AH AH (13) AH (In)noAS 239. 33/4 mol. 3py and entropy for the= -9.21 kml-51.5 kJ)-(-55.19k) - (22.6k)) AH na ons-18.91mol-137-2-18.91AH°=AS°=-9.2kmHopefully close if not tub. Compare your results to the values calculated above and try to account for any "differences.c. Use the free energy data in the table above to calculate the free energy for the reactionand use this value to calculate an equilibrium constant for the reaction at 25°C.(AG-RTInKq)productof tqmom u alibas my enemastaya sbibdini shiboiAG₁ =Keq1. Compare your value of the equilibrium constant to value in the question above and tryto account for any differences.ome of the Learning Objectives of this experiment are listed on the first page of thisperiment. Did you achieve the Learning Objectives? Explain your answer.

Step 1:Given thermodynamical data:To find: the enthalpy change and the entropy change for the…

Answered: 312 7. The NBS Tables of Chemical…

Chemistry

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Determine the enthalpy change of the universe (delta Suniverseo) in J K-1 at 25oC for the reaction and information given in the picture.
A novel inorganic compound has two different crystalline forms, namely blue and red crystals. The physical and thermodynamic properties of blue and red crystals are given below. Mw of the novel inorganic compound is 86.54 g mol1. Properties (T = 298 K, P = 1.00 bar) Blue Red AH; (kJ mol 1) -1722.6 -1722.9 AG (KJ mol 1) -1648.5 -1647.1 Sin (U K1 mol 1) 86.4 81.2 CPm (JK1 mol 1) 66.5 65.7 Density (g mL 1) 2.145 2.278 What pressure must be achieved to induce the conversion of blue to red crystal at T = 298 K? Assume both blue and red crystals are incompressible at T = 298 K. Answer in bar to 0 decimal place (e.g. 1762)
Calculate (a) the (molar) Gibbs energy of mixing, (b) the(molar) entropy of mixing when the two major componentsof air (nitrogen and oxygen) are mixed to form air at 298 K.The mole fractions of N2 and 0 2 are 0.78 and 0.22. respectively. (c) Is the mixing spontaneous?
(2) The Gibbs function G is (GF) ₁ P == ound ·S (06), = relationship (25) a = -(=++) ₂ thu modynamic property. If =V, prove the following
Gibbs free energy (G) is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, and is minimized at equilibrium. It is defined as G=H-TS where H is enthalpy, T is temperature, and S is entropy. The chemical reaction that causes iron to corrode in air is given by 4Fe+302-2Fe2O3 TXn in which at 298 K, AH ASixn - 543.7 J/K. H = - 1684 kJ and Part A What is the standard Gibbs free energy for this reaction? Assume the commonly used standard reference temperature of 298 K. Express your answer as an integer and include the appropriate units. ► View Available Hint(s) AGrxn Submit μÅ Value t Ć Units ?
The reduction of iron(III) oxide (Fe2O3) to pure iron during the first step of steelmaking, 2 Fe2O3(s) 4Fe(s) + 302 (g) is driven by the high-temperature combustion of coke, a purified form of coal: C(s) + O2(g) - - CO2(g) Suppose at the temperature of a blast furnace the Gibbs free energies of formation AG of CO2 and Fe2O3 are -428. kJ/mol and -821. kJ/mol, respectively. Calculate the minimum mass of coke needed to produce 680. t of pure iron. (One metric ton, symbol t, equals 1000 kg.) Round your answer to 2 significant digits.
The change in Gibbs energy that accompanies the combustion of C6H12O6(s) to carbon dioxide and water vapour at 25 °c is -2828 kJ mol-1. The potential energy of an object of mass m at a height h, relative to that at the Earth's surface is given by mgh, where g = 9.81 m s-2 is the acceleration of freefall. How much glucose does a person of mass 65 kg need to consume to climb through 10m?
Calculate the change in S when one mole of water is heated from 263 to 283 K given the molar capacities inJ.K-1 , Cp(ice) = 2.09 + 0.126T, Cp(water)=75.3, and change in Hm=6000Jmol-1
(a)At 0 oC, liquid water and ice are in equilibrium at standard pressure, so they have the SAME molar Gibbs energy. When raise from 1.0 bar to 100 bar, how much Gibbs free energy change in the liquid phase ? (molar mass of water 18 g mol-1; mass density of ice = 0.9150 g cm-3; mass density of liquid water, 0.9999 g cm-3) Set the initial Gibbs energy = 0 if you like. (b) how much Gibbs free energy change in the solid phase? c) under this process according to your calculation , solid changes to liquid. Liquid changes to solid
The temperature dependence of the heat capacity of non-metallic solids is found to follow the Debye T3 -law at very low temperatures, with Cp,m = aT3. (a) Derive an expression for the change in molar entropy on heating for such a solid. (b) For solid nitrogen, a= 6.15 x 10-3 J K-4 mol-1. What is the molar entropy of solid nitrogen at 5 K?
Without carrying out an explicit calculation, explain there lative values of the standard molar entropies (at 298 K) of the following substances: (a) Ne(g) (146 J K-1 mol-1) compared with Xe(g) (170 J K-1 mol-1), (b) H2O(g) (189 J K-1 mol-1) compared with D2O(g) (198 J K-1 mol-1), (c) C(diamond) (2.4 J K-1 mol-1) compared with C(g raphite) (5.7 J K-1 mol-1).
Thermodynamics and enthalpy (Chemistry)

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