312 7. The NBS Tables of Chemical Thermodynamic Properties in the Journal of Physical & Chemical Reference Data, Vol. 11, 1982, p 252, report the following data: E Sp ΔΗ AG kJ/mol kJ/mol J/K-mol KI2(aq) 55.19 -51.57 111.3 A 12(aq) 22.6 m 16.46 137.2 PI,(aq) 51.5) -51.4 239.3 a. Using the data in the table, use Hess's law to calculate the triiodide formation. 12 (99) +1 (99) → 15 (ad) AH AH (13) AH (In) no AS 239. 33/4 mol. 3py and entropy for the = -9.21 kml -51.5 kJ)-(-55.19k) - (22.6k)) AH na ons -18.91 mol-137-2 -18.91 AH°= AS°= -9.2km Hopefully close if not tu b. Compare your results to the values calculated above and try to account for any " differences. c. Use the free energy data in the table above to calculate the free energy for the reaction and use this value to calculate an equilibrium constant for the reaction at 25°C. (AG-RTInKq) product of tqmom u alibas my enemastaya sbibdini shiboi AG₁ = Keq 1. Compare your value of the equilibrium constant to value in the question above and try to account for any differences. ome of the Learning Objectives of this experiment are listed on the first page of this periment. Did you achieve the Learning Objectives? Explain your answer.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section16.5: Entropy And The Second Law Of Thermodynamics
Problem 16.4PSP
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312
7. The NBS Tables of Chemical Thermodynamic Properties in the Journal of Physical &
Chemical Reference Data, Vol. 11, 1982, p 252, report the following data:
E
Sp
ΔΗ
AG
kJ/mol
kJ/mol
J/K-mol
KI2(aq)
55.19
-51.57
111.3
A
12(aq)
22.6 m 16.46
137.2
PI,(aq)
51.5)
-51.4
239.3
a. Using the data in the table, use Hess's law to calculate the
triiodide formation.
12 (99) +1 (99) → 15 (ad)
AH AH (13) AH (In)
no
AS 239. 33/4 mol. 3py and entropy for the
= -9.21 kml
-51.5 kJ)-(-55.19k) - (22.6k)) AH na ons
-18.91
mol-137-2
-18.91
AH°=
AS°=
-9.2km
Hopefully close if not tu
b. Compare your results to the values calculated above and try to account for any "
differences.
c. Use the free energy data in the table above to calculate the free energy for the reaction
and use this value to calculate an equilibrium constant for the reaction at 25°C.
(AG-RTInKq)
product
of tqmom u alibas my enemastaya sbibdini shiboi
AG₁ =
Keq
1. Compare your value of the equilibrium constant to value in the question above and try
to account for any differences.
ome of the Learning Objectives of this experiment are listed on the first page of this
periment. Did you achieve the Learning Objectives? Explain your answer.
Transcribed Image Text:312 7. The NBS Tables of Chemical Thermodynamic Properties in the Journal of Physical & Chemical Reference Data, Vol. 11, 1982, p 252, report the following data: E Sp ΔΗ AG kJ/mol kJ/mol J/K-mol KI2(aq) 55.19 -51.57 111.3 A 12(aq) 22.6 m 16.46 137.2 PI,(aq) 51.5) -51.4 239.3 a. Using the data in the table, use Hess's law to calculate the triiodide formation. 12 (99) +1 (99) → 15 (ad) AH AH (13) AH (In) no AS 239. 33/4 mol. 3py and entropy for the = -9.21 kml -51.5 kJ)-(-55.19k) - (22.6k)) AH na ons -18.91 mol-137-2 -18.91 AH°= AS°= -9.2km Hopefully close if not tu b. Compare your results to the values calculated above and try to account for any " differences. c. Use the free energy data in the table above to calculate the free energy for the reaction and use this value to calculate an equilibrium constant for the reaction at 25°C. (AG-RTInKq) product of tqmom u alibas my enemastaya sbibdini shiboi AG₁ = Keq 1. Compare your value of the equilibrium constant to value in the question above and try to account for any differences. ome of the Learning Objectives of this experiment are listed on the first page of this periment. Did you achieve the Learning Objectives? Explain your answer.
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