pH 2 4 12 10 8 Titration Data Titration Curve of a Diprotic Organic Acid 1st Equivalence Point (12.0 mL) 2nd Equivalence Point (24.8 mL) 1st Halfway Point (6.0 mL, pH = 2.63) 2nd Halfway Point (18.4 mL, pH = 9.2) pKa29.2 Ka₂ = 6.31 x 10-10 pka 63 2.39 × 10-3 0 5 10 15 20 20 Volume of NaOH (mL) 25 9.2 pH 2.63 pH 1st equivalence point 12ml 1st halfway point 6 ml 2nd halfway point 18.2 ml 2nd equivalence point 24.8
pH 2 4 12 10 8 Titration Data Titration Curve of a Diprotic Organic Acid 1st Equivalence Point (12.0 mL) 2nd Equivalence Point (24.8 mL) 1st Halfway Point (6.0 mL, pH = 2.63) 2nd Halfway Point (18.4 mL, pH = 9.2) pKa29.2 Ka₂ = 6.31 x 10-10 pka 63 2.39 × 10-3 0 5 10 15 20 20 Volume of NaOH (mL) 25 9.2 pH 2.63 pH 1st equivalence point 12ml 1st halfway point 6 ml 2nd halfway point 18.2 ml 2nd equivalence point 24.8
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter8: Acids And Bases
Section: Chapter Questions
Problem 8.15P: 8-15 Write an equation for the reaction that takes place when each base is added to water. (a) LiOH...
Related questions
Question
Write a one or two paragraphs of
-what was study in identification of a Weak Diprotic Acid using Titration
-Summarize what happened in these results shown below
-what results did this experiment end up with whether this lab was successful or not
Transcribed Image Text:pH
2
4
12
10
8
Titration Data
Titration Curve of a Diprotic Organic Acid
1st Equivalence Point (12.0 mL)
2nd Equivalence Point (24.8 mL)
1st Halfway Point (6.0 mL, pH = 2.63)
2nd Halfway Point (18.4 mL, pH = 9.2)
pKa29.2
Ka₂ = 6.31 x 10-10
pka
63
2.39 × 10-3
0
5
10
15
20
20
Volume of NaOH (mL)
25
Transcribed Image Text:9.2 pH
2.63 pH
1st equivalence point
12ml
1st halfway point
6 ml
2nd halfway point
18.2 ml
2nd equivalence point
24.8
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