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- I have a half size breadboard,9V source, multimeter, 220 resistor, (forward biased) 1N914 diode, in series. Im reading about 9.7mA. The simulation reads close to 36mA. Can you help me to figure out if I am doing something wrong. (I lfet the battery a little unhooked so the resistor would not overheat). This image shows how I set up my circuit I need to read current first than volage the simulation has another multimeter we are to relace with a jumper wire to read voltage of the diode. We first must read circuit currrent.Help me answer, I want to check my solution To get the contribution of the 75V source to iR, we first kill the 50mA source. What is the resulting equivalent resistance in series with the 75K resistor (in Kohms) To get the contribution of the 75V source to iR, we first kill the 50mA source. What is the resulting value of iR (in mA)? What is the nodal equation for Vx? What is the Thevanin voltage in (Volts) and Thevanin resistance in (Kohms)?A 150V moving iron volt meter intended for 50Hz has an inductance of 0.7H and a resistance of 3K ohm. Find the series resistance required to extend the range of instrument to 300V if this 300V - 50Hz instrument used to measure dc voltage find the dc voltage when the scale reading is 200V
- Please show step by step working with neat sketch of the graph thank you.(please handwrite solutions)Please in typing format please ASAP for the like please clear the Please answer in typing format please ASAP for please ASAP for likeThis is a practice problem from the Introduction to Electronics course in my Electrical Engineering program. Could you please walk me through the steps of solving it so that I can solve more complicated ones in the future? Thank you for your assistance.
- Considering the circuit in the following figure, if V1 varies between -20 V and 0 V and Vb=5V, then the current through V1 is (assume ideal diodes): * D1 D2 4 ko 2 kO V1 Vo Vb -8 V O a. ((V1 +5)/4) mA for V1 2 -5 V and Zero for V1 s -5 V O b. ((V1 -5)) mA for V1 s - 5 V and Zero for V1 2 -5 V Oc. ((V1 +5)/4) mA for V1 s - 5 V and Zero for V1 2 - 5 V O d. ((V1 +5)/4) mA for V1 s 5 V and Zero for V1 2 5 Vplease solve in 25 minutes i really need help i will give you positive feedbackDraw and label a voltage divider that generates 0.5V from an input of 1.5V. Then draw and label a current divider that generates 1.25A from an input of1.0A. Pleaseclearlydefine/label the value of all variables (e.g. resistances). If a solution does not exist, then simply state so.
- lell L1 R Ro 2. In this figure, assume arbitrary numbers for R1, R2, L1, and L2 including some number for the battery E. Find the rate of current in which inductor one (L1) is changing just after the switch is closed. Next, find the current in L1 after some time after the switch has been closed. lellProblem 3 -10t The current flowin through a 5 H coil is given by 12e7 A. Find an expresion for the voltage, power, and stored energy. Sketch the waveforms to scale for the current, voltage, power, and energy from t = 0 to t = 500 ms.180 is the answer amount of ohms needed on the oscilliscope. I need to transpose the equation to solve for R. I must work out an equation that equals 180 ohms R resistance that gives off 50mA of current using the transposed equation. Series impedence ,inductive reactive, phase angle formulas may need to be used. I need to get as close to 180 ohms as possible.